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A hiker stands on the edge of a cliff 490 m above the ground and throws a stone horizontally with a speed of 15 m s-1. The time taken by the stone to reach the ground is
  • a)
    5 s
  • b)
    10 s
  • c)
    12 s
  • d)
    15 s
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A hiker stands on the edge of a cliff 490 m above the ground and throw...
Here, u = 15ms−1
h = 490m
Time taken by the stone to reach the ground is
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Community Answer
A hiker stands on the edge of a cliff 490 m above the ground and throw...
Given:
- Height of the cliff (h) = 490 m
- Initial horizontal velocity of the stone (u) = 15 m/s
- Acceleration due to gravity (g) = 9.8 m/s²

Assumptions:
- The stone is thrown horizontally, so there is no vertical initial velocity (vy = 0).
- There is no air resistance.

Calculating time taken by the stone to reach the ground:
1. We can break the motion of the stone into horizontal and vertical components.
2. The horizontal component of the stone's motion is uniform and unaffected by gravity. Therefore, the time taken to reach the ground horizontally is the same as the time taken by the stone to fall vertically from the cliff.
3. We can calculate the time taken for the stone to fall vertically using the equation:
h = (1/2) * g * t² [where h is the height, g is the acceleration due to gravity, and t is the time]
4. Rearranging the equation, we get:
t = sqrt(2h/g)
Substituting the given values, we have:
t = sqrt(2 * 490 / 9.8)
t = sqrt(980/9.8)
t = sqrt(100)
t = 10 seconds

Conclusion:
The time taken by the stone to reach the ground is 10 seconds (option B).
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