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An iron block of sides 50 cm x 8 cm x 15 cm has to be pushed along the lloor. The force required will be niinimum_when the surface in contact with ground is
  • a)
    8 cm x 15 cm surface
  • b)
    50 cm x 15 cm surface
  • c)
    8 cm x 50 cm surface
  • d)
    force is same for all surfaces
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
An iron block of sides 50 cm x 8 cm x 15 cm has to be pushed along the...
**Explanation:**

When an object is pushed along the floor, the force required to move it depends on the friction between the object and the floor. The frictional force is given by the equation:

Frictional force (F) = coefficient of friction (µ) * Normal force (N)

The coefficient of friction depends on the nature of the surfaces in contact. The normal force is the force exerted by the object on the floor perpendicular to the surface. In this case, the weight of the iron block provides the normal force.

The weight of the iron block is given by the equation:

Weight (W) = mass (m) * acceleration due to gravity (g)

Since the mass of the iron block is constant and the acceleration due to gravity is constant, the weight is constant.

**Analysis:**

To determine the minimum force required to push the iron block, we need to analyze the different surfaces in contact with the ground.

1. **8 cm x 15 cm surface:**
If the iron block is pushed along this surface, the area of contact with the ground is 8 cm x 15 cm = 120 cm². The normal force acting on this surface is the weight of the iron block, which is constant.

2. **50 cm x 15 cm surface:**
If the iron block is pushed along this surface, the area of contact with the ground is 50 cm x 15 cm = 750 cm². The normal force acting on this surface is the weight of the iron block, which is constant.

3. **8 cm x 50 cm surface:**
If the iron block is pushed along this surface, the area of contact with the ground is 8 cm x 50 cm = 400 cm². The normal force acting on this surface is the weight of the iron block, which is constant.

**Conclusion:**

Since the normal force remains the same for all surfaces in contact with the ground, and the coefficient of friction does not change, the frictional force and hence the force required to push the iron block will be the same for all surfaces. Therefore, the correct answer is option 'D' - force is the same for all surfaces.
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An iron block of sides 50 cm x 8 cm x 15 cm has to be pushed along the...
D
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An iron block of sides 50 cm x 8 cm x 15 cm has to be pushed along the lloor. The force required will be niinimum_when the surface in contact with ground isa)8 cm x 15 cm surfaceb)50 cm x 15 cm surfacec)8 cm x 50 cm surfaced)force is same for all surfacesCorrect answer is option 'D'. Can you explain this answer?
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An iron block of sides 50 cm x 8 cm x 15 cm has to be pushed along the lloor. The force required will be niinimum_when the surface in contact with ground isa)8 cm x 15 cm surfaceb)50 cm x 15 cm surfacec)8 cm x 50 cm surfaced)force is same for all surfacesCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An iron block of sides 50 cm x 8 cm x 15 cm has to be pushed along the lloor. The force required will be niinimum_when the surface in contact with ground isa)8 cm x 15 cm surfaceb)50 cm x 15 cm surfacec)8 cm x 50 cm surfaced)force is same for all surfacesCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An iron block of sides 50 cm x 8 cm x 15 cm has to be pushed along the lloor. The force required will be niinimum_when the surface in contact with ground isa)8 cm x 15 cm surfaceb)50 cm x 15 cm surfacec)8 cm x 50 cm surfaced)force is same for all surfacesCorrect answer is option 'D'. Can you explain this answer?.
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