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A person in an elevator accelerating upwards with an acceleration of 2 m s-2, tosses a coin vertically upwards with a speed of 20 m s-1. After how much time will the coin fall back into his hand? (Take g = 10 m s-2)
- a)5/3s
- b)3/10s
- c)10/3s
- d)3/5s
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A person in an elevator accelerating upwards with an acceleration of 2...
To find the time taken for the coin to fall back into the person's hand, we need to consider the motion of the coin in the elevator frame.
Let's analyze the motion of the coin in two parts:
1. When the coin is moving upwards against gravity.
2. When the coin is moving downwards under the influence of gravity.
1. Motion of the coin when moving upwards against gravity:
In this case, the acceleration of the coin is the sum of the acceleration due to gravity and the acceleration of the elevator.
Acceleration of the coin, a' = g + a (upwards)
where g = 10 m/s^2 (acceleration due to gravity) and a = 2 m/s^2 (acceleration of the elevator).
Since the coin is moving upwards, its initial velocity, u' = 20 m/s (upwards)
Using the equation of motion: v' = u' + a' t
where v' is the final velocity, t is the time taken, and a' is the acceleration of the coin.
When the coin reaches its highest point, its final velocity becomes zero. Therefore, we can write:
0 = 20 + (10 + 2) t
0 = 20 + 12t
12t = -20
t = -20/12
t = -5/3 s
However, time cannot be negative, so we ignore this solution.
2. Motion of the coin when moving downwards under the influence of gravity:
In this case, the acceleration of the coin is the acceleration due to gravity, which is 10 m/s^2 (downwards).
The initial velocity of the coin when it starts moving downwards is zero since it reaches its highest point at the top. Therefore, u = 0.
Using the equation of motion: v = u + gt
where v is the final velocity, t is the time taken, and g is the acceleration due to gravity.
When the coin falls back into the person's hand, its final velocity is 20 m/s (downwards).
20 = 0 + 10t
10t = 20
t = 20/10
t = 2 s
Therefore, the time taken for the coin to fall back into the person's hand is 2 seconds.
Hence, the correct answer is option C) 10/3 s.
Let's analyze the motion of the coin in two parts:
1. When the coin is moving upwards against gravity.
2. When the coin is moving downwards under the influence of gravity.
1. Motion of the coin when moving upwards against gravity:
In this case, the acceleration of the coin is the sum of the acceleration due to gravity and the acceleration of the elevator.
Acceleration of the coin, a' = g + a (upwards)
where g = 10 m/s^2 (acceleration due to gravity) and a = 2 m/s^2 (acceleration of the elevator).
Since the coin is moving upwards, its initial velocity, u' = 20 m/s (upwards)
Using the equation of motion: v' = u' + a' t
where v' is the final velocity, t is the time taken, and a' is the acceleration of the coin.
When the coin reaches its highest point, its final velocity becomes zero. Therefore, we can write:
0 = 20 + (10 + 2) t
0 = 20 + 12t
12t = -20
t = -20/12
t = -5/3 s
However, time cannot be negative, so we ignore this solution.
2. Motion of the coin when moving downwards under the influence of gravity:
In this case, the acceleration of the coin is the acceleration due to gravity, which is 10 m/s^2 (downwards).
The initial velocity of the coin when it starts moving downwards is zero since it reaches its highest point at the top. Therefore, u = 0.
Using the equation of motion: v = u + gt
where v is the final velocity, t is the time taken, and g is the acceleration due to gravity.
When the coin falls back into the person's hand, its final velocity is 20 m/s (downwards).
20 = 0 + 10t
10t = 20
t = 20/10
t = 2 s
Therefore, the time taken for the coin to fall back into the person's hand is 2 seconds.
Hence, the correct answer is option C) 10/3 s.
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Community Answer
A person in an elevator accelerating upwards with an acceleration of 2...
Here, v = 20m s−1, a = 2m s−2, g = 10m s−2
The coin will fall back into the person’s hand after t s.
∴ t =
= 10/3s
The coin will fall back into the person’s hand after t s.
∴ t =
= 10/3s
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A person in an elevator accelerating upwards with an acceleration of 2 m s-2, tosses a coin vertically upwards with a speed of 20 m s-1. After how much time will the coin fall back into his hand? (Take g = 10 m s-2)a)5/3sb)3/10sc)10/3sd)3/5sCorrect answer is option 'C'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A person in an elevator accelerating upwards with an acceleration of 2 m s-2, tosses a coin vertically upwards with a speed of 20 m s-1. After how much time will the coin fall back into his hand? (Take g = 10 m s-2)a)5/3sb)3/10sc)10/3sd)3/5sCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A person in an elevator accelerating upwards with an acceleration of 2 m s-2, tosses a coin vertically upwards with a speed of 20 m s-1. After how much time will the coin fall back into his hand? (Take g = 10 m s-2)a)5/3sb)3/10sc)10/3sd)3/5sCorrect answer is option 'C'. Can you explain this answer?.
A person in an elevator accelerating upwards with an acceleration of 2 m s-2, tosses a coin vertically upwards with a speed of 20 m s-1. After how much time will the coin fall back into his hand? (Take g = 10 m s-2)a)5/3sb)3/10sc)10/3sd)3/5sCorrect answer is option 'C'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A person in an elevator accelerating upwards with an acceleration of 2 m s-2, tosses a coin vertically upwards with a speed of 20 m s-1. After how much time will the coin fall back into his hand? (Take g = 10 m s-2)a)5/3sb)3/10sc)10/3sd)3/5sCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A person in an elevator accelerating upwards with an acceleration of 2 m s-2, tosses a coin vertically upwards with a speed of 20 m s-1. After how much time will the coin fall back into his hand? (Take g = 10 m s-2)a)5/3sb)3/10sc)10/3sd)3/5sCorrect answer is option 'C'. Can you explain this answer?.
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