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One end of a string of length I is connected to a particle of mass m and the other to a small peg on a smooth horizontal table. If the particle moves in a circle with speed v, the net force on the particle directed towards the centre is (where T is the tension in the string)
- a)T
- b)T - mv2 / l
- c)T + mv2 / l
- d)0
Correct answer is option 'A'. Can you explain this answer?
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One end of a string of length I is connected to a particle of mass m a...
The net force on the particle directed towards the center T.
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One end of a string of length I is connected to a particle of mass m a...
To understand why the net force on the particle directed towards the center is equal to the tension in the string, let's break down the forces acting on the particle.
1. Tension in the string (T): The tension in the string is the force exerted by the string on the particle. It is directed towards the center of the circle and is responsible for keeping the particle moving in a circular path.
2. Centripetal force (Fc): The net force on the particle directed towards the center is the centripetal force. It is responsible for the circular motion of the particle and is given by the equation Fc = mv^2/r, where m is the mass of the particle, v is its speed, and r is the radius of the circle.
3. Gravitational force (mg): The particle has a mass m and is subject to the gravitational force mg acting downwards. This force is perpendicular to the direction of motion and does not contribute to the net force towards the center.
Now, let's see why the net force on the particle directed towards the center is equal to the tension in the string (option A: T).
- Since the particle is moving in a circle with a constant speed v, there must be a net force directed towards the center. This net force is provided by the tension in the string.
- The tension in the string (T) is the only force acting on the particle in the direction towards the center. It balances the centripetal force required to keep the particle moving in a circular path.
- The gravitational force (mg) does not contribute to the net force towards the center as it acts perpendicular to the direction of motion.
Therefore, the net force on the particle directed towards the center is equal to the tension in the string (option A: T).
1. Tension in the string (T): The tension in the string is the force exerted by the string on the particle. It is directed towards the center of the circle and is responsible for keeping the particle moving in a circular path.
2. Centripetal force (Fc): The net force on the particle directed towards the center is the centripetal force. It is responsible for the circular motion of the particle and is given by the equation Fc = mv^2/r, where m is the mass of the particle, v is its speed, and r is the radius of the circle.
3. Gravitational force (mg): The particle has a mass m and is subject to the gravitational force mg acting downwards. This force is perpendicular to the direction of motion and does not contribute to the net force towards the center.
Now, let's see why the net force on the particle directed towards the center is equal to the tension in the string (option A: T).
- Since the particle is moving in a circle with a constant speed v, there must be a net force directed towards the center. This net force is provided by the tension in the string.
- The tension in the string (T) is the only force acting on the particle in the direction towards the center. It balances the centripetal force required to keep the particle moving in a circular path.
- The gravitational force (mg) does not contribute to the net force towards the center as it acts perpendicular to the direction of motion.
Therefore, the net force on the particle directed towards the center is equal to the tension in the string (option A: T).
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One end of a string of length I is connected to a particle of mass m and the other to a small peg on a smooth horizontal table. If the particle moves in a circle with speed v, the net force on the particle directed towards the centre is (where T is the tension in the string)a)Tb)T - mv2 / lc)T + mv2 / ld)0Correct answer is option 'A'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about One end of a string of length I is connected to a particle of mass m and the other to a small peg on a smooth horizontal table. If the particle moves in a circle with speed v, the net force on the particle directed towards the centre is (where T is the tension in the string)a)Tb)T - mv2 / lc)T + mv2 / ld)0Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One end of a string of length I is connected to a particle of mass m and the other to a small peg on a smooth horizontal table. If the particle moves in a circle with speed v, the net force on the particle directed towards the centre is (where T is the tension in the string)a)Tb)T - mv2 / lc)T + mv2 / ld)0Correct answer is option 'A'. Can you explain this answer?.
One end of a string of length I is connected to a particle of mass m and the other to a small peg on a smooth horizontal table. If the particle moves in a circle with speed v, the net force on the particle directed towards the centre is (where T is the tension in the string)a)Tb)T - mv2 / lc)T + mv2 / ld)0Correct answer is option 'A'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about One end of a string of length I is connected to a particle of mass m and the other to a small peg on a smooth horizontal table. If the particle moves in a circle with speed v, the net force on the particle directed towards the centre is (where T is the tension in the string)a)Tb)T - mv2 / lc)T + mv2 / ld)0Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One end of a string of length I is connected to a particle of mass m and the other to a small peg on a smooth horizontal table. If the particle moves in a circle with speed v, the net force on the particle directed towards the centre is (where T is the tension in the string)a)Tb)T - mv2 / lc)T + mv2 / ld)0Correct answer is option 'A'. Can you explain this answer?.
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