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A stone of mass 5 kg is tied to a string of length 10 m is whirled round in a horizontal circle. Wha is the maximum speed with which the stone can be whirled around if the string can witbstand a maximum tension of 200 N.
- a)10 m s-1
- b)15 m s-1
- c)20 m s-1
- d)25 m s-1
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A stone of mass 5 kg is tied to a string of length 10 m is whirled rou...
Here, m = 5kg , r = 10m, Tmax = 200N
As Tmax =
∴
∴
= 400
⇒ vmax =20 m s−1
As Tmax =
∴
∴
= 400
⇒ vmax =20 m s−1
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Community Answer
A stone of mass 5 kg is tied to a string of length 10 m is whirled rou...
To find the maximum speed with which the stone can be whirled around, we need to consider the tension force acting on the string. The tension force provides the centripetal force required to keep the stone moving in a circular path.
Let's analyze the problem step by step:
1. Determine the centripetal force:
The centripetal force acting on the stone is given by the equation Fc = mv²/r, where Fc is the centripetal force, m is the mass of the stone, v is the velocity, and r is the radius of the circular path.
2. Determine the maximum tension:
The string can withstand a maximum tension of 200 N. Therefore, the maximum tension force in the string should be equal to or less than this value.
3. Relate tension with centripetal force:
The tension force in the string is equal to the centripetal force required to keep the stone moving in a circular path. Thus, we have T = Fc.
4. Substitute the values:
In this case, the radius of the circular path is given as 10 m, and the mass of the stone is given as 5 kg. We need to find the maximum velocity.
Using the equation T = Fc = mv²/r, we can rearrange it to solve for velocity:
v = √(Tr/m)
Plugging in the values, we get
v = √(200 * 10 / 5) = √(400) = 20 m/s
Therefore, the maximum speed with which the stone can be whirled around is 20 m/s, which corresponds to option C.
Let's analyze the problem step by step:
1. Determine the centripetal force:
The centripetal force acting on the stone is given by the equation Fc = mv²/r, where Fc is the centripetal force, m is the mass of the stone, v is the velocity, and r is the radius of the circular path.
2. Determine the maximum tension:
The string can withstand a maximum tension of 200 N. Therefore, the maximum tension force in the string should be equal to or less than this value.
3. Relate tension with centripetal force:
The tension force in the string is equal to the centripetal force required to keep the stone moving in a circular path. Thus, we have T = Fc.
4. Substitute the values:
In this case, the radius of the circular path is given as 10 m, and the mass of the stone is given as 5 kg. We need to find the maximum velocity.
Using the equation T = Fc = mv²/r, we can rearrange it to solve for velocity:
v = √(Tr/m)
Plugging in the values, we get
v = √(200 * 10 / 5) = √(400) = 20 m/s
Therefore, the maximum speed with which the stone can be whirled around is 20 m/s, which corresponds to option C.
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A stone of mass 5 kg is tied to a string of length 10 m is whirled round in a horizontal circle. Wha is the maximum speed with which the stone canbe whirled around if the string can witbstand a maximum tension of 200 N.a)10 m s-1b)15 m s-1c)20 m s-1d)25 m s-1Correct answer is option 'C'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A stone of mass 5 kg is tied to a string of length 10 m is whirled round in a horizontal circle. Wha is the maximum speed with which the stone canbe whirled around if the string can witbstand a maximum tension of 200 N.a)10 m s-1b)15 m s-1c)20 m s-1d)25 m s-1Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A stone of mass 5 kg is tied to a string of length 10 m is whirled round in a horizontal circle. Wha is the maximum speed with which the stone canbe whirled around if the string can witbstand a maximum tension of 200 N.a)10 m s-1b)15 m s-1c)20 m s-1d)25 m s-1Correct answer is option 'C'. Can you explain this answer?.
A stone of mass 5 kg is tied to a string of length 10 m is whirled round in a horizontal circle. Wha is the maximum speed with which the stone canbe whirled around if the string can witbstand a maximum tension of 200 N.a)10 m s-1b)15 m s-1c)20 m s-1d)25 m s-1Correct answer is option 'C'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A stone of mass 5 kg is tied to a string of length 10 m is whirled round in a horizontal circle. Wha is the maximum speed with which the stone canbe whirled around if the string can witbstand a maximum tension of 200 N.a)10 m s-1b)15 m s-1c)20 m s-1d)25 m s-1Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A stone of mass 5 kg is tied to a string of length 10 m is whirled round in a horizontal circle. Wha is the maximum speed with which the stone canbe whirled around if the string can witbstand a maximum tension of 200 N.a)10 m s-1b)15 m s-1c)20 m s-1d)25 m s-1Correct answer is option 'C'. Can you explain this answer?.
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