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Which of the following shows dsp2 hybridisation and a square planar geometry?
- a)SF6
- b)BeF5
- c)PCl5
- d)[Ni(CN)4]2-
Correct answer is option 'D'. Can you explain this answer?
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Which of the following shows dsp2 hybridisation and a square planar ge...
Understanding dsp2 Hybridisation
d) [Ni(CN)4]2- is a classic example of dsp2 hybridisation leading to a square planar geometry. Let's break down the reasoning:
Coordination Number
- The coordination number of [Ni(CN)4]2- is 4, indicating that nickel is surrounded by four cyanide ligands.
- A square planar geometry is often observed in transition metal complexes with a coordination number of 4.
Hybridisation Process
- In [Ni(CN)4]2-, nickel has the electronic configuration of [Ar] 3d8 4s2.
- To accommodate four ligands, one 4s and three 3d orbitals hybridise to form four dsp2 hybrid orbitals.
- The d orbitals involved are from the 3d subshell, while s and p orbitals are from the 4th shell.
Geometry of the Complex
- The dsp2 hybrid orbitals arrange themselves in a square planar manner to minimize electron pair repulsion.
- The ligands (cyanide in this case) are positioned at the corners of a square, with the metal ion at the center.
Comparison with Other Options
- a) SF6 has sp3d2 hybridisation and octahedral geometry.
- b) BeF5 is trigonal bipyramidal and involves sp3d hybridisation.
- c) PCl5 features sp3d hybridisation and has a trigonal bipyramidal geometry.
Conclusion
- Hence, [Ni(CN)4]2- exemplifies dsp2 hybridisation and square planar geometry, making it the correct answer among the provided options.
d) [Ni(CN)4]2- is a classic example of dsp2 hybridisation leading to a square planar geometry. Let's break down the reasoning:
Coordination Number
- The coordination number of [Ni(CN)4]2- is 4, indicating that nickel is surrounded by four cyanide ligands.
- A square planar geometry is often observed in transition metal complexes with a coordination number of 4.
Hybridisation Process
- In [Ni(CN)4]2-, nickel has the electronic configuration of [Ar] 3d8 4s2.
- To accommodate four ligands, one 4s and three 3d orbitals hybridise to form four dsp2 hybrid orbitals.
- The d orbitals involved are from the 3d subshell, while s and p orbitals are from the 4th shell.
Geometry of the Complex
- The dsp2 hybrid orbitals arrange themselves in a square planar manner to minimize electron pair repulsion.
- The ligands (cyanide in this case) are positioned at the corners of a square, with the metal ion at the center.
Comparison with Other Options
- a) SF6 has sp3d2 hybridisation and octahedral geometry.
- b) BeF5 is trigonal bipyramidal and involves sp3d hybridisation.
- c) PCl5 features sp3d hybridisation and has a trigonal bipyramidal geometry.
Conclusion
- Hence, [Ni(CN)4]2- exemplifies dsp2 hybridisation and square planar geometry, making it the correct answer among the provided options.
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Which of the following shows dsp2 hybridisation and a square planar geometry?a)SF6b)BeF5c)PCl5d)[Ni(CN)4]2-Correct answer is option 'D'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Which of the following shows dsp2 hybridisation and a square planar geometry?a)SF6b)BeF5c)PCl5d)[Ni(CN)4]2-Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following shows dsp2 hybridisation and a square planar geometry?a)SF6b)BeF5c)PCl5d)[Ni(CN)4]2-Correct answer is option 'D'. Can you explain this answer?.
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