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A steam of water flowing horizontally with a speed of 25 m s-1 gushes out of a tube of cross sectional area 10-3 m2, and hits a vertical wall nearby. What is the force exerted on the wall by the impact of water?
- a)125 N
- b)625 N
- c)-650 N
- d)-1125 N
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A steam of water flowing horizontally with a speed of 25 m s-1 gushes ...
Here, u = 25 m s-1, v = 0, t = 1, A = 10-3 m2
Density of water p = 1000 kgm-3
Mass of water gushed out per second, m
= volume x density / time = area x distance x density / time
= Area x velocity x density
= 10-3 x 25 x 1000 = 25 kg
F =
= 625 N
F' = F = 625N
Density of water p = 1000 kgm-3
Mass of water gushed out per second, m
= volume x density / time = area x distance x density / time
= Area x velocity x density
= 10-3 x 25 x 1000 = 25 kg
F =
= 625 NF' = F = 625N
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Community Answer
A steam of water flowing horizontally with a speed of 25 m s-1 gushes ...
To find the force exerted on the wall by the impact of water, we can use the equation:
Force = mass × acceleration
1. Find the mass of the water:
The mass can be calculated using the equation:
mass = density × volume
The density of water is approximately 1000 kg/m³, and the volume of water flowing per second can be calculated by multiplying the cross-sectional area of the tube by the velocity of the water:
volume = area × velocity
Substituting the given values:
volume = (10^-3 m²) × (25 m/s) = 0.025 kg/s
2. Calculate the acceleration:
Since the water is hitting the wall and coming to rest, we can assume that the final velocity is 0 m/s. The initial velocity is given as 25 m/s. Using the equation:
acceleration = (final velocity - initial velocity) / time
The time taken to come to rest is not given, so we can assume it to be 1 second for simplicity:
acceleration = (0 m/s - 25 m/s) / 1 s = -25 m/s²
Note that the negative sign indicates that the acceleration is in the opposite direction to the initial velocity.
3. Calculate the force:
Using the equation:
Force = mass × acceleration
Substituting the values:
Force = (0.025 kg/s) × (-25 m/s²) = -0.625 N
The negative sign indicates that the force is in the opposite direction to the initial velocity.
Therefore, the force exerted on the wall by the impact of water is -0.625 N, which is approximately -625 N in the correct significant figures.
Hence, the correct answer is option B) 625 N.
Force = mass × acceleration
1. Find the mass of the water:
The mass can be calculated using the equation:
mass = density × volume
The density of water is approximately 1000 kg/m³, and the volume of water flowing per second can be calculated by multiplying the cross-sectional area of the tube by the velocity of the water:
volume = area × velocity
Substituting the given values:
volume = (10^-3 m²) × (25 m/s) = 0.025 kg/s
2. Calculate the acceleration:
Since the water is hitting the wall and coming to rest, we can assume that the final velocity is 0 m/s. The initial velocity is given as 25 m/s. Using the equation:
acceleration = (final velocity - initial velocity) / time
The time taken to come to rest is not given, so we can assume it to be 1 second for simplicity:
acceleration = (0 m/s - 25 m/s) / 1 s = -25 m/s²
Note that the negative sign indicates that the acceleration is in the opposite direction to the initial velocity.
3. Calculate the force:
Using the equation:
Force = mass × acceleration
Substituting the values:
Force = (0.025 kg/s) × (-25 m/s²) = -0.625 N
The negative sign indicates that the force is in the opposite direction to the initial velocity.
Therefore, the force exerted on the wall by the impact of water is -0.625 N, which is approximately -625 N in the correct significant figures.
Hence, the correct answer is option B) 625 N.
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A steam of water flowing horizontally with a speed of 25 m s-1 gushes out of a tube of cross sectional area 10-3 m2, and hits a verticalwall nearby. What is the force exerted on the wall by the impact of water?a)125 Nb)625 Nc)-650 Nd)-1125 NCorrect answer is option 'B'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A steam of water flowing horizontally with a speed of 25 m s-1 gushes out of a tube of cross sectional area 10-3 m2, and hits a verticalwall nearby. What is the force exerted on the wall by the impact of water?a)125 Nb)625 Nc)-650 Nd)-1125 NCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A steam of water flowing horizontally with a speed of 25 m s-1 gushes out of a tube of cross sectional area 10-3 m2, and hits a verticalwall nearby. What is the force exerted on the wall by the impact of water?a)125 Nb)625 Nc)-650 Nd)-1125 NCorrect answer is option 'B'. Can you explain this answer?.
A steam of water flowing horizontally with a speed of 25 m s-1 gushes out of a tube of cross sectional area 10-3 m2, and hits a verticalwall nearby. What is the force exerted on the wall by the impact of water?a)125 Nb)625 Nc)-650 Nd)-1125 NCorrect answer is option 'B'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A steam of water flowing horizontally with a speed of 25 m s-1 gushes out of a tube of cross sectional area 10-3 m2, and hits a verticalwall nearby. What is the force exerted on the wall by the impact of water?a)125 Nb)625 Nc)-650 Nd)-1125 NCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A steam of water flowing horizontally with a speed of 25 m s-1 gushes out of a tube of cross sectional area 10-3 m2, and hits a verticalwall nearby. What is the force exerted on the wall by the impact of water?a)125 Nb)625 Nc)-650 Nd)-1125 NCorrect answer is option 'B'. Can you explain this answer?.
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