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Given below are few mixtures formed by mixing two components. Which of the following binary mixtures will have same composition in liquid and vapour phase?

(i) Ethanol + Chloroform

(ii) Nitric acid + Water

(iii) Benzene + Toluene

(iv) Ethyl chloride + Ethyl bromide

  • a)
    (i) and (iii)

  • b)
    (iii) and (iv)

  • c)
    (i), (ii) and (iii)

  • d)
    (i) and (ii)

Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Given below are few mixtures formed by mixing two components. Which of...
(iii) and (iv) will form ideal solutions hence do not form azeotropes. Azeotropes have same composition in liquid and vapour form when distilled.


To determine which binary mixtures will have the same composition in the liquid and vapor phases, we need to identify mixtures that form ideal solutions. In an ideal solution, the composition of the liquid phase and the vapor phase is the same at equilibrium.


Here’s a brief analysis of each mixture:




  1. Ethanol + Chloroform:



    • This mixture does not behave ideally due to strong hydrogen bonding interactions between ethanol and chloroform, which can cause deviations from Raoult's Law.




  2. Nitric Acid + Water:



    • Nitric acid and water form a non-ideal solution. Nitric acid forms strong hydrogen bonds with water, resulting in significant deviations from ideal behavior. Thus, the composition in the liquid and vapor phases will not be the same.




  3. Benzene + Toluene:



    • Benzene and toluene form an ideal solution. The interactions between benzene and toluene are similar, and thus the composition of the liquid and vapor phases will be the same.




  4. Ethyl Chloride + Ethyl Bromide:



    • Ethyl chloride and ethyl bromide also form an ideal solution. The interactions between these two similar substances lead to minimal deviations from ideal behavior.





Based on the above analyses, the mixtures that will have the same composition in the liquid and vapor phases are:


2. (iii) and (iv)


So the correct answer is:


2. (iii) and (iv)
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Most Upvoted Answer
Given below are few mixtures formed by mixing two components. Which of...
To determine which binary mixture will have the same composition in the liquid and vapor phase, we need to consider the concept of azeotropes.

An azeotrope is a mixture of two or more liquids that boils at a constant temperature and has the same composition in both the liquid and vapor phases. In other words, the composition of the liquid and the composition of the vapor are identical.

Let's analyze each binary mixture given in the options:

(i) Ethanol - Chloroform:
- Ethanol and chloroform do not form an azeotrope. The boiling points of ethanol and chloroform are significantly different, and their compositions in the liquid and vapor phases will not be the same. Therefore, this mixture does not have the same composition in the liquid and vapor phases.

(ii) Nitric acid - Water:
- Nitric acid and water do form an azeotrope called nitric acid-water azeotrope. The boiling point of this mixture is lower than the boiling point of pure nitric acid. The composition of the liquid and vapor phases will be the same. Hence, this mixture has the same composition in the liquid and vapor phases.

(iii) Benzene - Toluene:
- Benzene and toluene do not form an azeotrope. The boiling points of benzene and toluene are close, but not identical. The compositions in the liquid and vapor phases will not be the same. Therefore, this mixture does not have the same composition in the liquid and vapor phases.

(iv) Ethyl chloride - Ethyl bromide:
- Ethyl chloride and ethyl bromide do form an azeotrope called ethyl chloride-ethyl bromide azeotrope. The boiling point of this mixture is lower than the boiling point of pure ethyl bromide. The composition of the liquid and vapor phases will be the same. Hence, this mixture has the same composition in the liquid and vapor phases.

Based on the analysis, we can conclude that the binary mixtures (iii) Benzene - Toluene and (iv) Ethyl chloride - Ethyl bromide have the same composition in the liquid and vapor phases. Therefore, the correct answer is option B.
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