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A bullet of mass 40g moving with a speed of 90 ms-1 enters a heavy wooden block and is stopped after a distance of 60 cm. The average resistive force exerted by the block on the bullet is
- a)180 N
- b)220 N
- c)270 N
- d)320 N
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A bullet of mass 40g moving with a speed of 90 ms-1 enters a heavy woo...
Here, u = 90 ms−1, v = 0
m = 40gm = 4/1000kg = 0.04 kg, s = 60 cm = 0.6 m
Using v2 − u2 = 2as
∴ (0)2 − (90)2 = 2a × 0.6
-ve sign shows the retradation.
∴ The average resistive force exerted by block on the bullet is
F = m × a = (0.04kg)(6750ms−2) = 270N
m = 40gm = 4/1000kg = 0.04 kg, s = 60 cm = 0.6 m
Using v2 − u2 = 2as
∴ (0)2 − (90)2 = 2a × 0.6
-ve sign shows the retradation.
∴ The average resistive force exerted by block on the bullet is
F = m × a = (0.04kg)(6750ms−2) = 270N
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Community Answer
A bullet of mass 40g moving with a speed of 90 ms-1 enters a heavy woo...
Given:
- Mass of the bullet (m) = 40g = 0.04kg
- Initial velocity of the bullet (u) = 90 m/s
- Distance covered by the bullet in the wooden block (s) = 60 cm = 0.6 m
To find: The average resistive force exerted by the block on the bullet
Using the equation of motion:
v^2 = u^2 + 2as
where,
v = final velocity of the bullet (0 m/s, as it comes to rest)
a = acceleration of the bullet
s = distance covered by the bullet in the block
Solving for a, we get:
a = (v^2 - u^2) / (2s)
Substituting the given values, we have:
a = (0 - 90^2) / (2 * 0.6)
a = -8100 / 1.2
a = -6750 m/s^2
The negative sign indicates that the acceleration is in the opposite direction of the initial velocity of the bullet.
Using Newton's second law of motion:
F = ma
where,
F = force exerted by the block on the bullet
m = mass of the bullet
a = acceleration of the bullet
Substituting the values, we get:
F = 0.04 * (-6750)
F ≈ -270 N
The negative sign indicates that the force is in the opposite direction of the initial motion of the bullet.
Therefore, the average resistive force exerted by the block on the bullet is approximately 270 N, which corresponds to option C.
- Mass of the bullet (m) = 40g = 0.04kg
- Initial velocity of the bullet (u) = 90 m/s
- Distance covered by the bullet in the wooden block (s) = 60 cm = 0.6 m
To find: The average resistive force exerted by the block on the bullet
Using the equation of motion:
v^2 = u^2 + 2as
where,
v = final velocity of the bullet (0 m/s, as it comes to rest)
a = acceleration of the bullet
s = distance covered by the bullet in the block
Solving for a, we get:
a = (v^2 - u^2) / (2s)
Substituting the given values, we have:
a = (0 - 90^2) / (2 * 0.6)
a = -8100 / 1.2
a = -6750 m/s^2
The negative sign indicates that the acceleration is in the opposite direction of the initial velocity of the bullet.
Using Newton's second law of motion:
F = ma
where,
F = force exerted by the block on the bullet
m = mass of the bullet
a = acceleration of the bullet
Substituting the values, we get:
F = 0.04 * (-6750)
F ≈ -270 N
The negative sign indicates that the force is in the opposite direction of the initial motion of the bullet.
Therefore, the average resistive force exerted by the block on the bullet is approximately 270 N, which corresponds to option C.
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A bullet of mass 40g moving with a speed of 90 ms-1 enters a heavy wooden block and is stopped after a distance of 60 cm. The average resistive force exerted by the block on the bullet isa)180 Nb)220 Nc)270 Nd)320 NCorrect answer is option 'C'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A bullet of mass 40g moving with a speed of 90 ms-1 enters a heavy wooden block and is stopped after a distance of 60 cm. The average resistive force exerted by the block on the bullet isa)180 Nb)220 Nc)270 Nd)320 NCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bullet of mass 40g moving with a speed of 90 ms-1 enters a heavy wooden block and is stopped after a distance of 60 cm. The average resistive force exerted by the block on the bullet isa)180 Nb)220 Nc)270 Nd)320 NCorrect answer is option 'C'. Can you explain this answer?.
A bullet of mass 40g moving with a speed of 90 ms-1 enters a heavy wooden block and is stopped after a distance of 60 cm. The average resistive force exerted by the block on the bullet isa)180 Nb)220 Nc)270 Nd)320 NCorrect answer is option 'C'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A bullet of mass 40g moving with a speed of 90 ms-1 enters a heavy wooden block and is stopped after a distance of 60 cm. The average resistive force exerted by the block on the bullet isa)180 Nb)220 Nc)270 Nd)320 NCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bullet of mass 40g moving with a speed of 90 ms-1 enters a heavy wooden block and is stopped after a distance of 60 cm. The average resistive force exerted by the block on the bullet isa)180 Nb)220 Nc)270 Nd)320 NCorrect answer is option 'C'. Can you explain this answer?.
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