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The equivalent resistance of series combination of four equal resistors is S. If they are joined in parallel, the total resistance is P. The relation between S and P is given by S = nP. Then the minimum possible value of n is
  • a)
    12
  • b)
    14
  • c)
    16
  • d)
    10
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The equivalent resistance of series combination of four equal resistor...
Let Resistance of each resistor is = R
In series connection:
Req1 = 4R = S
R = S/4 → (1)
In parallel connection
Req2 = R4 = P
R = 4/P → (2)
Equating (1) and (2)
S/4 = 4P
S = 16P
n = 16
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Most Upvoted Answer
The equivalent resistance of series combination of four equal resistor...
Understanding Series and Parallel Resistance
The equivalent resistance of resistors varies based on their configuration. For four equal resistors (R) in series and parallel, we can derive the relationships.
Series Combination
- When resistors are in series, the total resistance (S) is calculated as:
S = R + R + R + R = 4R
Parallel Combination
- For the same resistors in parallel, the total resistance (P) is given by:
1/P = 1/R + 1/R + 1/R + 1/R = 4/R
- Thus, P can be derived as:
P = R/4
Relationship Between S and P
Given the relation S = nP, substituting the expressions for S and P gives us:
4R = n(R/4)
Solving for n
- Rearranging the equation leads to:
4R = nR/4
- Cancelling R (assuming R is not zero), we find:
4 = n/4
- Multiplying both sides by 4 results in:
n = 16
Conclusion
The minimum possible value of n, when four equal resistors are combined in series and parallel, is 16. Therefore, the correct answer is option 'C'.
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