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A parallel plate capacitor is charged and then isolated. What is the effect of increasing the plate separation on charge, potential, capacitance, respectively?
- a)constant, decreases, decreases
- b)increases, decreases, decreases
- c)constant, decreases, increases
- d)constant, increases, decreases
Correct answer is option 'D'. Can you explain this answer?
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A parallel plate capacitor is charged and then isolated. What is the e...
As the capacitor is isolated after charging, charge on it remains constant. Plate separation increases d, decreases C = ϵ0A/d and hence increases potential V = q/C.
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A parallel plate capacitor is charged and then isolated. What is the e...
Effect of increasing plate separation on a charged and isolated parallel plate capacitor:
Increasing the plate separation of a charged and isolated parallel plate capacitor has the following effects:
- Charge:
The charge on the capacitor remains constant. When a capacitor is charged, the charge on the plates is determined by the voltage applied and the capacitance of the capacitor. The charge does not depend on the plate separation.
- Potential:
As the plate separation is increased, the potential difference across the capacitor plates increases. This is because the potential difference is directly proportional to the electric field between the plates, which in turn is inversely proportional to the plate separation. Therefore, increasing the plate separation results in an increase in potential difference.
- Capacitance:
The capacitance of the capacitor decreases as the plate separation is increased. Capacitance is inversely proportional to the plate separation, as capacitance is a measure of the ability of a capacitor to store charge per unit voltage. When the plate separation is increased, the ability of the capacitor to store charge decreases, resulting in a decrease in capacitance.
Therefore, the correct answer is option 'D': constant charge, increased potential, and decreased capacitance when the plate separation of a charged and isolated parallel plate capacitor is increased.
Increasing the plate separation of a charged and isolated parallel plate capacitor has the following effects:
- Charge:
The charge on the capacitor remains constant. When a capacitor is charged, the charge on the plates is determined by the voltage applied and the capacitance of the capacitor. The charge does not depend on the plate separation.
- Potential:
As the plate separation is increased, the potential difference across the capacitor plates increases. This is because the potential difference is directly proportional to the electric field between the plates, which in turn is inversely proportional to the plate separation. Therefore, increasing the plate separation results in an increase in potential difference.
- Capacitance:
The capacitance of the capacitor decreases as the plate separation is increased. Capacitance is inversely proportional to the plate separation, as capacitance is a measure of the ability of a capacitor to store charge per unit voltage. When the plate separation is increased, the ability of the capacitor to store charge decreases, resulting in a decrease in capacitance.
Therefore, the correct answer is option 'D': constant charge, increased potential, and decreased capacitance when the plate separation of a charged and isolated parallel plate capacitor is increased.
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A parallel plate capacitor is charged and then isolated. What is the effect of increasing the plate separation on charge, potential, capacitance, respectively?a)constant, decreases, decreasesb)increases, decreases, decreasesc)constant, decreases, increasesd)constant, increases, decreasesCorrect answer is option 'D'. Can you explain this answer?
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