A uniform electric field E = 2 x 103N C-1is acting along the positive ...
Flux of Electric Field through a Square
Given:
Electric field, E = 2 x 10^3 N C^-1 (acting along the positive x-axis)
Side of the square, a = 10 cm = 0.1 m
To find:
The flux of the electric field through the square.
Flux of Electric Field:
The flux of an electric field through a surface is a measure of the number of field lines passing through that surface. It is given by the dot product of the electric field and the area vector of the surface.
Mathematically, the flux (Φ) is defined as:
Φ = E · A
Where E is the electric field vector and A is the area vector of the surface.
In this case, the electric field is uniform and directed along the positive x-axis. The square is parallel to the yz plane, which means its normal vector is along the x-axis. Therefore, the area vector of the square is also along the x-axis.
Since the electric field and the area vector are parallel, their dot product will be the product of their magnitudes.
Calculation:
Given that the electric field magnitude, E = 2 x 10^3 N C^-1, and the side of the square, a = 0.1 m.
The area of the square, A = a^2 = (0.1 m)^2 = 0.01 m^2.
Now, we can calculate the flux using the formula:
Φ = E · A = (2 x 10^3 N C^-1) · (0.01 m^2)
Φ = 20 N C^-1 m^2
Therefore, the flux of the electric field through the square is 20 N C^-1 m^2.
Hence, the correct answer is option 'A' (20 N C^-1 m^2).
A uniform electric field E = 2 x 103N C-1is acting along the positive ...
Here, E = 2 x 103 N C-1 is along + x-axis
Surface area, s = (10 cm)2 = 102 x 10-4 m2 = 10-2 m2
When plane is parallel to yz plane, θ = 0°
So φ = E s cosθ = 2 x 103 x 10-2 cos 0° = 20N C-1 m2