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A force of 2.25 N acts on a charge of 15 x 10-4 C. The intensity of electric field at that point is
  • a)
    150 N C-1
  • b)
    15 N C-1
  • c)
    1500 N C-1
  • d)
    1.5 N C-1
Correct answer is option 'C'. Can you explain this answer?
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Understanding Electric Field Intensity
To determine the intensity of the electric field (E) at a point where a force (F) is acting on a charge (q), we use the formula:
E = F / q
Where:
- E is the electric field intensity in N/C (Newtons per Coulomb)
- F is the force acting on the charge in Newtons (N)
- q is the magnitude of the charge in Coulombs (C)
Given Data
- Force (F) = 2.25 N
- Charge (q) = 15 x 10^-4 C
Calculating Electric Field Intensity
Substituting the given values into the formula:
- E = 2.25 N / (15 x 10^-4 C)
To simplify the division:
- Convert 15 x 10^-4 C to standard decimal form:
- 15 x 10^-4 = 0.0015 C
Now, plug this value into the equation:
- E = 2.25 N / 0.0015 C
Performing the calculation:
- E = 1500 N/C
Conclusion
Thus, the intensity of the electric field at that point is 1500 N/C.
The correct answer is option 'C'.
This demonstrates how the force and charge relate to the electric field intensity, a fundamental concept in electromagnetism, especially relevant for NEET preparation.
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