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A wire with 15 Ω resistance is stretched by one tenth of its original length and volume of wire is kept constant. Then its resistance will be
  • a)
    15.18Ω
  • b)
    81.15Ω 
  • c)
    51.18Ω
  • d)
    18.15Ω
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
A wire with 15 Ω resistance is stretched by one tenth of its ori...
If the wire is stretched by (1/10)th of its original length then the new length of wire become

As the volume of wire remains constant then
⇒ 
Now the resistance of stretched wire.

 
∴ 
= 18.15Ω
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Community Answer
A wire with 15 Ω resistance is stretched by one tenth of its ori...
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