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A wire with 15 Ω resistance is stretched by one tenth of its original length and volume of wire is kept constant. Then its resistance will be
  • a)
    15.18Ω
  • b)
    81.15Ω 
  • c)
    51.18Ω
  • d)
    18.15Ω
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A wire with 15 Ω resistance is stretched by one tenth of its ori...
If the wire is stretched by (1/10)th of its original length then the new length of wire become

As the volume of wire remains constant then
⇒ 
Now the resistance of stretched wire.

 
∴ 
= 18.15Ω
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Most Upvoted Answer
A wire with 15 Ω resistance is stretched by one tenth of its ori...
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A wire with 15 Ω resistance is stretched by one tenth of its original length and volume of wire is kept constant. Then its resistance will bea)15.18Ωb)81.15Ωc)51.18Ωd)18.15ΩCorrect answer is option 'D'. Can you explain this answer?
Question Description
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