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In the question number 18, the potential at a point 20cm from the mid-point of the line joining the two charges in a plane normal to the line and passing through the mid-point is
  • a)
    1.4 × 105 V
  • b)
    4.2 × 103 V
  • c)
    2.9 × 104 V
  • d)
    3.7 × 105 V
Correct answer is option 'A'. Can you explain this answer?
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In the question number 18, the potential at a point 20cm from the mid-...
From the figure, potential at P,



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In the question number 18, the potential at a point 20cm from the mid-...
The potential at a point 20 cm from the mid-point of the line joining the two charges can be found using the formula for the potential due to a point charge:

V = k * q / r

where V is the potential, k is the electrostatic constant (9 x 10^9 Nm^2/C^2), q is the charge, and r is the distance from the charge.

Since the charges are equal in magnitude and opposite in sign, the potential at the midpoint of the line joining the charges is zero. Therefore, the potential at a point 20 cm from the mid-point is the same as the potential due to one of the charges at that distance.

Using the formula above, we can calculate the potential:

V = (9 x 10^9 Nm^2/C^2) * (1.6 x 10^-19 C) / (0.2 m)

V ≈ 1.44 V

Therefore, the potential at a point 20 cm from the mid-point of the line joining the two charges is approximately 1.44 V.
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