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In Carius method of estimation of halogen, 0.15 g of an organic compound gave 0.12 g of AgBr. What is the percentage of bromine in the compound?
- a)68.08%
- b)34.04%
- c)42.1%
- d)50%
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
In Carius method of estimation of halogen, 0.15 g of an organic compou...
Given:
- Mass of organic compound = 0.15 g
- Mass of AgBr = 0.12 g
To find:
- Percentage of bromine in the compound
Explanation:
The Carius method is used to estimate the halogen content in an organic compound. In this method, the organic compound is heated with fuming nitric acid (HNO3) to convert the halogens present into their respective silver halides. The silver halides are then weighed to determine the halogen content.
Step 1: Find the molar mass of AgBr:
- The molar mass of AgBr can be calculated using the atomic masses of silver (Ag) and bromine (Br).
- Atomic mass of Ag = 107.87 g/mol
- Atomic mass of Br = 79.90 g/mol
- Molar mass of AgBr = Atomic mass of Ag + Atomic mass of Br = 107.87 + 79.90 = 187.77 g/mol
Step 2: Calculate the moles of AgBr:
- Moles of AgBr = Mass of AgBr / Molar mass of AgBr = 0.12 g / 187.77 g/mol = 0.000638 mol
Step 3: Determine the moles of bromine:
- Since 1 mole of AgBr contains 1 mole of bromine, the moles of bromine in the compound are also 0.000638 mol.
Step 4: Calculate the percentage of bromine:
- Percentage of bromine = (Moles of bromine / Moles of compound) x 100
- Moles of compound = Mass of compound / Molar mass of compound = 0.15 g / Molar mass of compound
Step 5: Substitute the values and calculate the percentage:
- Percentage of bromine = (0.000638 mol / (0.15 g / Molar mass of compound)) x 100
Step 6: Simplify the equation:
- Percentage of bromine = (0.000638 mol / (0.15 g / Molar mass of compound)) x 100
- Percentage of bromine = (0.000638 mol x Molar mass of compound / 0.15 g) x 100
- Percentage of bromine = (0.000638 x Molar mass of compound / 0.15) x 100
Step 7: Substitute the given values:
- Percentage of bromine = (0.000638 x Molar mass of compound / 0.15) x 100
Step 8: Substitute the molar mass of AgBr:
- Percentage of bromine = (0.000638 x 187.77 / 0.15) x 100
Step 9: Simplify the equation:
- Percentage of bromine = 0.06808 x Molar mass of compound
Step 10: Find the molar mass of the compound:
- Since the molar mass of the compound is not given, we cannot calculate the exact percentage of bromine.
- However, we can determine the relative percentage of bromine based on
- Mass of organic compound = 0.15 g
- Mass of AgBr = 0.12 g
To find:
- Percentage of bromine in the compound
Explanation:
The Carius method is used to estimate the halogen content in an organic compound. In this method, the organic compound is heated with fuming nitric acid (HNO3) to convert the halogens present into their respective silver halides. The silver halides are then weighed to determine the halogen content.
Step 1: Find the molar mass of AgBr:
- The molar mass of AgBr can be calculated using the atomic masses of silver (Ag) and bromine (Br).
- Atomic mass of Ag = 107.87 g/mol
- Atomic mass of Br = 79.90 g/mol
- Molar mass of AgBr = Atomic mass of Ag + Atomic mass of Br = 107.87 + 79.90 = 187.77 g/mol
Step 2: Calculate the moles of AgBr:
- Moles of AgBr = Mass of AgBr / Molar mass of AgBr = 0.12 g / 187.77 g/mol = 0.000638 mol
Step 3: Determine the moles of bromine:
- Since 1 mole of AgBr contains 1 mole of bromine, the moles of bromine in the compound are also 0.000638 mol.
Step 4: Calculate the percentage of bromine:
- Percentage of bromine = (Moles of bromine / Moles of compound) x 100
- Moles of compound = Mass of compound / Molar mass of compound = 0.15 g / Molar mass of compound
Step 5: Substitute the values and calculate the percentage:
- Percentage of bromine = (0.000638 mol / (0.15 g / Molar mass of compound)) x 100
Step 6: Simplify the equation:
- Percentage of bromine = (0.000638 mol / (0.15 g / Molar mass of compound)) x 100
- Percentage of bromine = (0.000638 mol x Molar mass of compound / 0.15 g) x 100
- Percentage of bromine = (0.000638 x Molar mass of compound / 0.15) x 100
Step 7: Substitute the given values:
- Percentage of bromine = (0.000638 x Molar mass of compound / 0.15) x 100
Step 8: Substitute the molar mass of AgBr:
- Percentage of bromine = (0.000638 x 187.77 / 0.15) x 100
Step 9: Simplify the equation:
- Percentage of bromine = 0.06808 x Molar mass of compound
Step 10: Find the molar mass of the compound:
- Since the molar mass of the compound is not given, we cannot calculate the exact percentage of bromine.
- However, we can determine the relative percentage of bromine based on
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Community Answer
In Carius method of estimation of halogen, 0.15 g of an organic compou...
Molar mass of AgBr = 108 + 80 = 188 g mol-1
Percentage of Br2 =
Percentage of Br2 =
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In Carius method of estimation of halogen, 0.15 g of an organic compound gave 0.12 g of AgBr. What is the percentage of bromine in the compound?a)68.08%b)34.04%c)42.1%d)50%Correct answer is option 'B'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In Carius method of estimation of halogen, 0.15 g of an organic compound gave 0.12 g of AgBr. What is the percentage of bromine in the compound?a)68.08%b)34.04%c)42.1%d)50%Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In Carius method of estimation of halogen, 0.15 g of an organic compound gave 0.12 g of AgBr. What is the percentage of bromine in the compound?a)68.08%b)34.04%c)42.1%d)50%Correct answer is option 'B'. Can you explain this answer?.
In Carius method of estimation of halogen, 0.15 g of an organic compound gave 0.12 g of AgBr. What is the percentage of bromine in the compound?a)68.08%b)34.04%c)42.1%d)50%Correct answer is option 'B'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In Carius method of estimation of halogen, 0.15 g of an organic compound gave 0.12 g of AgBr. What is the percentage of bromine in the compound?a)68.08%b)34.04%c)42.1%d)50%Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In Carius method of estimation of halogen, 0.15 g of an organic compound gave 0.12 g of AgBr. What is the percentage of bromine in the compound?a)68.08%b)34.04%c)42.1%d)50%Correct answer is option 'B'. Can you explain this answer?.
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