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If a long straight wire carries a current of 40 A, then the magnitude ol the field B at a point 15 cm away from the wire is 
  • a)
    5.34 x 10-5 T
  • b)
    8.34 x 10-5 T
  • c)
    9.6 x 10-5 T
  • d)
    10.2 x 10-5 T
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
If a long straight wire carries a current of 40 A, then the magnitude ...
Calculating the Magnetic Field at a Point 15 cm Away from a Current-Carrying Wire
To calculate the magnetic field at a point 15 cm away from a long straight wire carrying a current of 40 A, we can use the formula for the magnetic field around a current-carrying wire.

Formula for Magnetic Field around a Current-Carrying Wire:
The formula to calculate the magnetic field (B) around a long straight wire is given by:
\[ B = \frac{{\mu_0 \times I}}{2\pi \times r} \]
where:
- B is the magnetic field,
- \(\mu_0\) is the permeability of free space (\(4\pi \times 10^{-7} T \cdot m/A\)),
- I is the current flowing through the wire, and
- r is the distance from the wire.

Calculating the Magnetic Field:
Given:
- Current (I) = 40 A
- Distance from the wire (r) = 15 cm = 0.15 m
Substitute the values into the formula:
\[ B = \frac{{4\pi \times 10^{-7} \times 40}}{2\pi \times 0.15} \]
\[ B = \frac{{1.6 \times 10^{-5}}}{0.3} \]
\[ B = 5.34 \times 10^{-5} T \]
Therefore, the magnitude of the magnetic field at a point 15 cm away from the wire carrying a current of 40 A is 5.34 x 10^-5 T, which corresponds to option 'A'.
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Community Answer
If a long straight wire carries a current of 40 A, then the magnitude ...
I = 40A
r = 15 cm = 15 x 10-2 m
∴  = 5.34 x 10-5 T
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If a long straight wire carries a current of 40 A, then the magnitude ol the field B at a point 15 cm awayfrom the wire isa)5.34 x 10-5Tb)8.34 x 10-5Tc)9.6 x 10-5Td)10.2 x 10-5TCorrect answer is option 'A'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If a long straight wire carries a current of 40 A, then the magnitude ol the field B at a point 15 cm awayfrom the wire isa)5.34 x 10-5Tb)8.34 x 10-5Tc)9.6 x 10-5Td)10.2 x 10-5TCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If a long straight wire carries a current of 40 A, then the magnitude ol the field B at a point 15 cm awayfrom the wire isa)5.34 x 10-5Tb)8.34 x 10-5Tc)9.6 x 10-5Td)10.2 x 10-5TCorrect answer is option 'A'. Can you explain this answer?.
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