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The radii of curvature of the surfaces of a double convex lens are 20cm and 40cm respectively, and its focal length is 20cm. What is the refractive index of the material of the lens?
  • a)
    5/2
  • b)
    4/3
  • c)
    5/3
  • d)
    4/5
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The radii of curvature of the surfaces of a double convex lens are 20c...
Here, R1 = 20cm,R2 = −40cm, f = 20cm
Using lens makers formula we get,


⇒ μ = 5/3
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Most Upvoted Answer
The radii of curvature of the surfaces of a double convex lens are 20c...
Given:
Radii of curvature (R1) = 20 cm, (R2) = 40 cm
Focal length (f) = 20 cm

To find:
Refractive index (μ) of the material of the lens

Formula used:
1/f = (μ - 1) [1/R1 - 1/R2]

Calculation:
Substituting the given values in the above formula, we get:

1/20 = (μ - 1) [1/20 - 1/40]
1/20 = (μ - 1) [1/40]
2(μ - 1) = 1
μ - 1 = 1/2
μ = 1/2 + 1
μ = 3/2

Therefore, the refractive index of the material of the lens is 3/2.

Answer:
Option (c) 5/3.
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The radii of curvature of the surfaces of a double convex lens are 20cm and 40cm respectively, and its focal length is 20cm. What is the refractive index of the material of the lens?a)5/2b)4/3c)5/3d)4/5Correct answer is option 'C'. Can you explain this answer?
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