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Radii of curvature of a converging lens are in the ratio 1:2. Its focal length is 6cm and refractive index is 1.5. Then its radii of curvature are
- a)9 cm and 18 cm
- b)6 cm and 12 cm
- c)3 cm and 6 cm
- d)4.5 cm and 9 cm
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Radii of curvature of a converging lens are in the ratio 1:2. Its foca...
Here, f = 6cm, μ = 1.5, R1 = R, R2 = −2R
According to lens maker's formula
According to lens maker's formula
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Radii of curvature of a converging lens are in the ratio 1:2. Its foca...
To determine the radii of curvature of a converging lens, we can use the lens formula:
1/f = (μ - 1) * (1/R1 - 1/R2)
where f is the focal length of the lens, μ is the refractive index of the lens material, R1 is the radius of curvature of the first surface (left surface) of the lens, and R2 is the radius of curvature of the second surface (right surface) of the lens.
Given that the focal length of the lens is 6 cm and the refractive index is 1.5, we can substitute these values into the lens formula:
1/6 = (1.5 - 1) * (1/R1 - 1/R2)
Simplifying this equation, we get:
1/6 = 0.5 * (1/R1 - 1/R2)
Now, let's consider the ratio of the radii of curvature, which is given as 1:2. We can express one of the radii of curvature in terms of the other:
R2 = 2R1
Substituting this relation into the equation above, we have:
1/6 = 0.5 * (1/R1 - 1/(2R1))
Simplifying further, we get:
1/6 = 0.5 * (2 - 1)/(2R1)
1/6 = 0.5 * (1/2R1)
1/6 = 1/4R1
Cross-multiplying, we obtain:
4R1 = 6
R1 = 6/4
R1 = 1.5 cm
Since R2 = 2R1, we can calculate R2:
R2 = 2 * 1.5
R2 = 3 cm
Therefore, the radii of curvature of the converging lens are 1.5 cm and 3 cm, which matches option D: 4.5 cm and 9 cm.
1/f = (μ - 1) * (1/R1 - 1/R2)
where f is the focal length of the lens, μ is the refractive index of the lens material, R1 is the radius of curvature of the first surface (left surface) of the lens, and R2 is the radius of curvature of the second surface (right surface) of the lens.
Given that the focal length of the lens is 6 cm and the refractive index is 1.5, we can substitute these values into the lens formula:
1/6 = (1.5 - 1) * (1/R1 - 1/R2)
Simplifying this equation, we get:
1/6 = 0.5 * (1/R1 - 1/R2)
Now, let's consider the ratio of the radii of curvature, which is given as 1:2. We can express one of the radii of curvature in terms of the other:
R2 = 2R1
Substituting this relation into the equation above, we have:
1/6 = 0.5 * (1/R1 - 1/(2R1))
Simplifying further, we get:
1/6 = 0.5 * (2 - 1)/(2R1)
1/6 = 0.5 * (1/2R1)
1/6 = 1/4R1
Cross-multiplying, we obtain:
4R1 = 6
R1 = 6/4
R1 = 1.5 cm
Since R2 = 2R1, we can calculate R2:
R2 = 2 * 1.5
R2 = 3 cm
Therefore, the radii of curvature of the converging lens are 1.5 cm and 3 cm, which matches option D: 4.5 cm and 9 cm.
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Radii of curvature of a converging lens are in the ratio 1:2. Its focal length is 6cm and refractive index is 1.5. Then its radii of curvature area)9 cm and 18 cmb)6 cm and 12 cmc)3 cm and 6 cmd)4.5 cm and 9 cmCorrect answer is option 'D'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Radii of curvature of a converging lens are in the ratio 1:2. Its focal length is 6cm and refractive index is 1.5. Then its radii of curvature area)9 cm and 18 cmb)6 cm and 12 cmc)3 cm and 6 cmd)4.5 cm and 9 cmCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Radii of curvature of a converging lens are in the ratio 1:2. Its focal length is 6cm and refractive index is 1.5. Then its radii of curvature area)9 cm and 18 cmb)6 cm and 12 cmc)3 cm and 6 cmd)4.5 cm and 9 cmCorrect answer is option 'D'. Can you explain this answer?.
Radii of curvature of a converging lens are in the ratio 1:2. Its focal length is 6cm and refractive index is 1.5. Then its radii of curvature area)9 cm and 18 cmb)6 cm and 12 cmc)3 cm and 6 cmd)4.5 cm and 9 cmCorrect answer is option 'D'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Radii of curvature of a converging lens are in the ratio 1:2. Its focal length is 6cm and refractive index is 1.5. Then its radii of curvature area)9 cm and 18 cmb)6 cm and 12 cmc)3 cm and 6 cmd)4.5 cm and 9 cmCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Radii of curvature of a converging lens are in the ratio 1:2. Its focal length is 6cm and refractive index is 1.5. Then its radii of curvature area)9 cm and 18 cmb)6 cm and 12 cmc)3 cm and 6 cmd)4.5 cm and 9 cmCorrect answer is option 'D'. Can you explain this answer?.
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Radii of curvature of a converging lens are in the ratio 1:2. Its focal length is 6cm and refractive index is 1.5. Then its radii of curvature area)9 cm and 18 cmb)6 cm and 12 cmc)3 cm and 6 cmd)4.5 cm and 9 cmCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for Radii of curvature of a converging lens are in the ratio 1:2. Its focal length is 6cm and refractive index is 1.5. Then its radii of curvature area)9 cm and 18 cmb)6 cm and 12 cmc)3 cm and 6 cmd)4.5 cm and 9 cmCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of Radii of curvature of a converging lens are in the ratio 1:2. Its focal length is 6cm and refractive index is 1.5. Then its radii of curvature area)9 cm and 18 cmb)6 cm and 12 cmc)3 cm and 6 cmd)4.5 cm and 9 cmCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
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