NEET Exam > NEET Questions > 0.2 g of an organic compound contains C, H an...
Start Learning for Free
0.2 g of an organic compound contains C, H and O.On combustion, it yields 0.15 g CO2 and 0.12 g H2O.Ihe percentage of C, H and O respectively is
- a)C = 15%, H = 20%, O = 65%
- b)C = 10%, H = 8.2%, O = 81.8%
- c)C = 12.2%, H = 8.8%, O = 79%
- d)C = 20%, H = 6.66%, O = 73.34%
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
0.2 g of an organic compound contains C, H and O.On combustion, it yie...
% of O = 100 - (20 + 6.66) = 73.34%
Most Upvoted Answer
0.2 g of an organic compound contains C, H and O.On combustion, it yie...
Given:
Mass of organic compound = 0.2 g
Mass of CO2 produced = 0.15 g
Mass of H2O produced = 0.12 g
To find:
Percentage of C, H, and O in the compound
Let's assume that the organic compound is composed of carbon, hydrogen, and oxygen only.
Step 1: Calculate the moles of CO2 produced
Molar mass of CO2 = 12.01 g/mol (C) + 2 * 16.00 g/mol (O) = 44.01 g/mol
Moles of CO2 = Mass of CO2 / Molar mass of CO2 = 0.15 g / 44.01 g/mol = 0.0034 mol
Step 2: Calculate the moles of H2O produced
Molar mass of H2O = 2 * 1.01 g/mol (H) + 16.00 g/mol (O) = 18.02 g/mol
Moles of H2O = Mass of H2O / Molar mass of H2O = 0.12 g / 18.02 g/mol = 0.0067 mol
Step 3: Calculate the moles of carbon
Since 1 mole of CO2 contains 1 mole of carbon, moles of carbon = moles of CO2 = 0.0034 mol
Step 4: Calculate the moles of hydrogen
Since 1 mole of H2O contains 2 moles of hydrogen, moles of hydrogen = 2 * moles of H2O = 2 * 0.0067 mol = 0.0134 mol
Step 5: Calculate the moles of oxygen
Moles of oxygen = (moles of CO2 * 2) + moles of H2O = (0.0034 mol * 2) + 0.0067 mol = 0.0135 mol
Step 6: Calculate the percentage of each element
Percentage of carbon = (moles of carbon * molar mass of carbon) / mass of compound * 100
Percentage of carbon = (0.0034 mol * 12.01 g/mol) / 0.2 g * 100 = 20%
Percentage of hydrogen = (moles of hydrogen * molar mass of hydrogen) / mass of compound * 100
Percentage of hydrogen = (0.0134 mol * 1.01 g/mol) / 0.2 g * 100 = 6.66%
Percentage of oxygen = (moles of oxygen * molar mass of oxygen) / mass of compound * 100
Percentage of oxygen = (0.0135 mol * 16.00 g/mol) / 0.2 g * 100 = 73.34%
Therefore, the percentage of C, H, and O in the compound is:
C = 20%, H = 6.66%, O = 73.34%
Hence, the correct answer is option D.
Mass of organic compound = 0.2 g
Mass of CO2 produced = 0.15 g
Mass of H2O produced = 0.12 g
To find:
Percentage of C, H, and O in the compound
Let's assume that the organic compound is composed of carbon, hydrogen, and oxygen only.
Step 1: Calculate the moles of CO2 produced
Molar mass of CO2 = 12.01 g/mol (C) + 2 * 16.00 g/mol (O) = 44.01 g/mol
Moles of CO2 = Mass of CO2 / Molar mass of CO2 = 0.15 g / 44.01 g/mol = 0.0034 mol
Step 2: Calculate the moles of H2O produced
Molar mass of H2O = 2 * 1.01 g/mol (H) + 16.00 g/mol (O) = 18.02 g/mol
Moles of H2O = Mass of H2O / Molar mass of H2O = 0.12 g / 18.02 g/mol = 0.0067 mol
Step 3: Calculate the moles of carbon
Since 1 mole of CO2 contains 1 mole of carbon, moles of carbon = moles of CO2 = 0.0034 mol
Step 4: Calculate the moles of hydrogen
Since 1 mole of H2O contains 2 moles of hydrogen, moles of hydrogen = 2 * moles of H2O = 2 * 0.0067 mol = 0.0134 mol
Step 5: Calculate the moles of oxygen
Moles of oxygen = (moles of CO2 * 2) + moles of H2O = (0.0034 mol * 2) + 0.0067 mol = 0.0135 mol
Step 6: Calculate the percentage of each element
Percentage of carbon = (moles of carbon * molar mass of carbon) / mass of compound * 100
Percentage of carbon = (0.0034 mol * 12.01 g/mol) / 0.2 g * 100 = 20%
Percentage of hydrogen = (moles of hydrogen * molar mass of hydrogen) / mass of compound * 100
Percentage of hydrogen = (0.0134 mol * 1.01 g/mol) / 0.2 g * 100 = 6.66%
Percentage of oxygen = (moles of oxygen * molar mass of oxygen) / mass of compound * 100
Percentage of oxygen = (0.0135 mol * 16.00 g/mol) / 0.2 g * 100 = 73.34%
Therefore, the percentage of C, H, and O in the compound is:
C = 20%, H = 6.66%, O = 73.34%
Hence, the correct answer is option D.
|
Explore Courses for NEET exam
|
|
Top Courses for NEETView all
Question Description
0.2 g of an organic compound contains C, H and O.On combustion, it yields 0.15 g CO2 and 0.12 g H2O.Ihe percentage of C, H and O respectively isa)C = 15%, H = 20%, O = 65%b)C = 10%, H = 8.2%, O = 81.8%c)C = 12.2%, H = 8.8%, O = 79%d)C = 20%, H = 6.66%, O = 73.34%Correct answer is option 'D'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 0.2 g of an organic compound contains C, H and O.On combustion, it yields 0.15 g CO2 and 0.12 g H2O.Ihe percentage of C, H and O respectively isa)C = 15%, H = 20%, O = 65%b)C = 10%, H = 8.2%, O = 81.8%c)C = 12.2%, H = 8.8%, O = 79%d)C = 20%, H = 6.66%, O = 73.34%Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 0.2 g of an organic compound contains C, H and O.On combustion, it yields 0.15 g CO2 and 0.12 g H2O.Ihe percentage of C, H and O respectively isa)C = 15%, H = 20%, O = 65%b)C = 10%, H = 8.2%, O = 81.8%c)C = 12.2%, H = 8.8%, O = 79%d)C = 20%, H = 6.66%, O = 73.34%Correct answer is option 'D'. Can you explain this answer?.
0.2 g of an organic compound contains C, H and O.On combustion, it yields 0.15 g CO2 and 0.12 g H2O.Ihe percentage of C, H and O respectively isa)C = 15%, H = 20%, O = 65%b)C = 10%, H = 8.2%, O = 81.8%c)C = 12.2%, H = 8.8%, O = 79%d)C = 20%, H = 6.66%, O = 73.34%Correct answer is option 'D'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 0.2 g of an organic compound contains C, H and O.On combustion, it yields 0.15 g CO2 and 0.12 g H2O.Ihe percentage of C, H and O respectively isa)C = 15%, H = 20%, O = 65%b)C = 10%, H = 8.2%, O = 81.8%c)C = 12.2%, H = 8.8%, O = 79%d)C = 20%, H = 6.66%, O = 73.34%Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 0.2 g of an organic compound contains C, H and O.On combustion, it yields 0.15 g CO2 and 0.12 g H2O.Ihe percentage of C, H and O respectively isa)C = 15%, H = 20%, O = 65%b)C = 10%, H = 8.2%, O = 81.8%c)C = 12.2%, H = 8.8%, O = 79%d)C = 20%, H = 6.66%, O = 73.34%Correct answer is option 'D'. Can you explain this answer?.
Solutions for 0.2 g of an organic compound contains C, H and O.On combustion, it yields 0.15 g CO2 and 0.12 g H2O.Ihe percentage of C, H and O respectively isa)C = 15%, H = 20%, O = 65%b)C = 10%, H = 8.2%, O = 81.8%c)C = 12.2%, H = 8.8%, O = 79%d)C = 20%, H = 6.66%, O = 73.34%Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of 0.2 g of an organic compound contains C, H and O.On combustion, it yields 0.15 g CO2 and 0.12 g H2O.Ihe percentage of C, H and O respectively isa)C = 15%, H = 20%, O = 65%b)C = 10%, H = 8.2%, O = 81.8%c)C = 12.2%, H = 8.8%, O = 79%d)C = 20%, H = 6.66%, O = 73.34%Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
0.2 g of an organic compound contains C, H and O.On combustion, it yields 0.15 g CO2 and 0.12 g H2O.Ihe percentage of C, H and O respectively isa)C = 15%, H = 20%, O = 65%b)C = 10%, H = 8.2%, O = 81.8%c)C = 12.2%, H = 8.8%, O = 79%d)C = 20%, H = 6.66%, O = 73.34%Correct answer is option 'D'. Can you explain this answer?, a detailed solution for 0.2 g of an organic compound contains C, H and O.On combustion, it yields 0.15 g CO2 and 0.12 g H2O.Ihe percentage of C, H and O respectively isa)C = 15%, H = 20%, O = 65%b)C = 10%, H = 8.2%, O = 81.8%c)C = 12.2%, H = 8.8%, O = 79%d)C = 20%, H = 6.66%, O = 73.34%Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of 0.2 g of an organic compound contains C, H and O.On combustion, it yields 0.15 g CO2 and 0.12 g H2O.Ihe percentage of C, H and O respectively isa)C = 15%, H = 20%, O = 65%b)C = 10%, H = 8.2%, O = 81.8%c)C = 12.2%, H = 8.8%, O = 79%d)C = 20%, H = 6.66%, O = 73.34%Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice 0.2 g of an organic compound contains C, H and O.On combustion, it yields 0.15 g CO2 and 0.12 g H2O.Ihe percentage of C, H and O respectively isa)C = 15%, H = 20%, O = 65%b)C = 10%, H = 8.2%, O = 81.8%c)C = 12.2%, H = 8.8%, O = 79%d)C = 20%, H = 6.66%, O = 73.34%Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup