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How many grams of NaOH are present in 250 mL of 0.5 M NaOH solution?
  • a)
    7.32 g
  • b)
    3.8 g
  • c)
    5g
  • d)
    0.5 g
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
How many grams of NaOH are present in 250 mL of 0.5 M NaOH solution?a)...
Solution:

Given:
Volume of NaOH solution = 250 mL
Molarity of NaOH solution = 0.5 M

To find:
Mass of NaOH present in the solution

Formula:
Molarity (M) = Number of moles (n) / Volume in liters (V)
Number of moles (n) = Molarity (M) x Volume in liters (V)

Conversion:
1 L = 1000 mL
1 mole of NaOH = 40 g

Calculation:
Step 1: Convert the volume from mL to L
250 mL = 250/1000 L = 0.25 L

Step 2: Calculate the number of moles of NaOH
Number of moles (n) = Molarity (M) x Volume in liters (V)
Number of moles (n) = 0.5 M x 0.25 L = 0.125 moles

Step 3: Convert the number of moles to grams
Mass of NaOH = Number of moles x Molar mass
Mass of NaOH = 0.125 moles x 40 g/mol = 5 g

Therefore, the mass of NaOH present in 250 mL of 0.5 M NaOH solution is 5 grams, which corresponds to option C.
Free Test
Community Answer
How many grams of NaOH are present in 250 mL of 0.5 M NaOH solution?a)...
No. of moles of NaOH

Mass of NaOH = 40 × 0.125 = 5g
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