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The edge length of a fcc is 508 pm. If the radius of cation is 110 pm, the radius of anion is
- a)110 pm
- b)220 pm
- c)285 pm
- d)144 pm
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
The edge length of a fcc is 508 pm. If the radius of cation is 110 pm,...
For fcc,
2(r+ + r-) = a
2(110 + r-) = 508
r- = 508/2 - 110 = 144 pm
2(r+ + r-) = a
2(110 + r-) = 508
r- = 508/2 - 110 = 144 pm
Most Upvoted Answer
The edge length of a fcc is 508 pm. If the radius of cation is 110 pm,...
Given data:
Edge length of fcc = 508 pm
Radius of cation = 110 pm
To find: Radius of anion
Formula for fcc:
In a fcc, each corner atom is shared by 8 unit cells and each face-centered atom is shared by 2 unit cells. Hence, the number of atoms per unit cell in a fcc is:
4 corner atoms × 1/8 + 6 face-centered atoms × 1/2 = 4 × 1/8 + 6 × 1/2 = 4
Formula for edge length:
The edge length of the fcc unit cell can be expressed in terms of the radius of the atoms as:
Edge length (a) = 4√2r
Where r is the radius of the atom
Solution:
Given, Edge length of fcc = 508 pm
Radius of cation = 110 pm
Using the formula,
508 = 4√2r
r = 508/4√2 = 70.8 pm (radius of each atom)
Let the radius of the anion be R.
Then, the distance between the centers of the cation and anion in the fcc is equal to the sum of their radii.
Distance between centers = 2R + 2r = 2(R + 70.8)
The distance between the centers of the atoms along the edge of the fcc unit cell is equal to the edge length of the unit cell.
Distance between centers = Edge length = 508 pm
Equating the two distances, we get:
2(R + 70.8) = 508
R + 70.8 = 254
R = 183.2 pm
Therefore, the radius of the anion is 183.2 pm, which is option D.
Edge length of fcc = 508 pm
Radius of cation = 110 pm
To find: Radius of anion
Formula for fcc:
In a fcc, each corner atom is shared by 8 unit cells and each face-centered atom is shared by 2 unit cells. Hence, the number of atoms per unit cell in a fcc is:
4 corner atoms × 1/8 + 6 face-centered atoms × 1/2 = 4 × 1/8 + 6 × 1/2 = 4
Formula for edge length:
The edge length of the fcc unit cell can be expressed in terms of the radius of the atoms as:
Edge length (a) = 4√2r
Where r is the radius of the atom
Solution:
Given, Edge length of fcc = 508 pm
Radius of cation = 110 pm
Using the formula,
508 = 4√2r
r = 508/4√2 = 70.8 pm (radius of each atom)
Let the radius of the anion be R.
Then, the distance between the centers of the cation and anion in the fcc is equal to the sum of their radii.
Distance between centers = 2R + 2r = 2(R + 70.8)
The distance between the centers of the atoms along the edge of the fcc unit cell is equal to the edge length of the unit cell.
Distance between centers = Edge length = 508 pm
Equating the two distances, we get:
2(R + 70.8) = 508
R + 70.8 = 254
R = 183.2 pm
Therefore, the radius of the anion is 183.2 pm, which is option D.
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The edge length of a fcc is 508 pm. If the radius of cation is 110 pm, the radius of anion isa)110 pmb)220 pmc)285 pmd)144 pmCorrect answer is option 'D'. Can you explain this answer?
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The edge length of a fcc is 508 pm. If the radius of cation is 110 pm, the radius of anion isa)110 pmb)220 pmc)285 pmd)144 pmCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The edge length of a fcc is 508 pm. If the radius of cation is 110 pm, the radius of anion isa)110 pmb)220 pmc)285 pmd)144 pmCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The edge length of a fcc is 508 pm. If the radius of cation is 110 pm, the radius of anion isa)110 pmb)220 pmc)285 pmd)144 pmCorrect answer is option 'D'. Can you explain this answer?.
The edge length of a fcc is 508 pm. If the radius of cation is 110 pm, the radius of anion isa)110 pmb)220 pmc)285 pmd)144 pmCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The edge length of a fcc is 508 pm. If the radius of cation is 110 pm, the radius of anion isa)110 pmb)220 pmc)285 pmd)144 pmCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The edge length of a fcc is 508 pm. If the radius of cation is 110 pm, the radius of anion isa)110 pmb)220 pmc)285 pmd)144 pmCorrect answer is option 'D'. Can you explain this answer?.
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