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5.The iron loss and full load copper loss of 100KVA 6600/400V olts single phase transformer are 600W ats and 900 Watts.Calculate the efficiency at full load and half load at 0.8 power factor lag.Calculate the load at which maximum efficiency is obtained and its magnitude at some power factor.?
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5.The iron loss and full load copper loss of 100KVA 6600/400V olts sin...
Calculation of Efficiency at Full Load and Half Load
Given,
- Transformer rating = 100 KVA
- Voltage rating = 6600/400 V (Single phase)
- Iron loss = 600 W
- Full load copper loss = 900 W
- Power factor = 0.8 lagging
At Full Load:
- Input power = Output power + losses
- Output power = Transformer rating x Power factor = 100 x 0.8 = 80 KVA
- Input power = 80 KVA + 600 W + 900 W = 80.5 KVA
- Efficiency = Output power / Input power x 100 = 80 / 80.5 x 100 = 99.38%
At Half Load:
- Output power = Transformer rating x Power factor = 100 x 0.8 x 0.5 = 40 KVA
- Input power = 40 KVA + 600 W + 900 W = 40.5 KVA
- Efficiency = Output power / Input power x 100 = 40 / 40.5 x 100 = 98.77%
Calculation of Load at Maximum Efficiency and its Magnitude
- Efficiency is maximum when copper losses = iron losses
- At maximum efficiency, copper losses = iron losses = 600 W
- Input power = Output power + losses
- Output power = Transformer rating x Power factor
- Input power = Output power + copper losses + iron losses
- Transformer rating x Power factor = Transformer rating x (Load power factor) + 600 W + 600 W
- Load power factor = (Transformer rating x Power factor - 1200 W) / Transformer rating
- Load power factor = (100 x 0.8 - 1200) / 100 = 0.68
- Load = Transformer rating x Load power factor = 100 x 0.68 = 68 KVA
Therefore, the load at which maximum efficiency is obtained is 68 KVA at a power factor of 0.68 lagging.
Given,
- Transformer rating = 100 KVA
- Voltage rating = 6600/400 V (Single phase)
- Iron loss = 600 W
- Full load copper loss = 900 W
- Power factor = 0.8 lagging
At Full Load:
- Input power = Output power + losses
- Output power = Transformer rating x Power factor = 100 x 0.8 = 80 KVA
- Input power = 80 KVA + 600 W + 900 W = 80.5 KVA
- Efficiency = Output power / Input power x 100 = 80 / 80.5 x 100 = 99.38%
At Half Load:
- Output power = Transformer rating x Power factor = 100 x 0.8 x 0.5 = 40 KVA
- Input power = 40 KVA + 600 W + 900 W = 40.5 KVA
- Efficiency = Output power / Input power x 100 = 40 / 40.5 x 100 = 98.77%
Calculation of Load at Maximum Efficiency and its Magnitude
- Efficiency is maximum when copper losses = iron losses
- At maximum efficiency, copper losses = iron losses = 600 W
- Input power = Output power + losses
- Output power = Transformer rating x Power factor
- Input power = Output power + copper losses + iron losses
- Transformer rating x Power factor = Transformer rating x (Load power factor) + 600 W + 600 W
- Load power factor = (Transformer rating x Power factor - 1200 W) / Transformer rating
- Load power factor = (100 x 0.8 - 1200) / 100 = 0.68
- Load = Transformer rating x Load power factor = 100 x 0.68 = 68 KVA
Therefore, the load at which maximum efficiency is obtained is 68 KVA at a power factor of 0.68 lagging.
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5.The iron loss and full load copper loss of 100KVA 6600/400V olts single phase transformer are 600W ats and 900 Watts.Calculate the efficiency at full load and half load at 0.8 power factor lag.Calculate the load at which maximum efficiency is obtained and its magnitude at some power factor.?
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5.The iron loss and full load copper loss of 100KVA 6600/400V olts single phase transformer are 600W ats and 900 Watts.Calculate the efficiency at full load and half load at 0.8 power factor lag.Calculate the load at which maximum efficiency is obtained and its magnitude at some power factor.? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about 5.The iron loss and full load copper loss of 100KVA 6600/400V olts single phase transformer are 600W ats and 900 Watts.Calculate the efficiency at full load and half load at 0.8 power factor lag.Calculate the load at which maximum efficiency is obtained and its magnitude at some power factor.? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 5.The iron loss and full load copper loss of 100KVA 6600/400V olts single phase transformer are 600W ats and 900 Watts.Calculate the efficiency at full load and half load at 0.8 power factor lag.Calculate the load at which maximum efficiency is obtained and its magnitude at some power factor.?.
5.The iron loss and full load copper loss of 100KVA 6600/400V olts single phase transformer are 600W ats and 900 Watts.Calculate the efficiency at full load and half load at 0.8 power factor lag.Calculate the load at which maximum efficiency is obtained and its magnitude at some power factor.? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about 5.The iron loss and full load copper loss of 100KVA 6600/400V olts single phase transformer are 600W ats and 900 Watts.Calculate the efficiency at full load and half load at 0.8 power factor lag.Calculate the load at which maximum efficiency is obtained and its magnitude at some power factor.? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 5.The iron loss and full load copper loss of 100KVA 6600/400V olts single phase transformer are 600W ats and 900 Watts.Calculate the efficiency at full load and half load at 0.8 power factor lag.Calculate the load at which maximum efficiency is obtained and its magnitude at some power factor.?.
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5.The iron loss and full load copper loss of 100KVA 6600/400V olts single phase transformer are 600W ats and 900 Watts.Calculate the efficiency at full load and half load at 0.8 power factor lag.Calculate the load at which maximum efficiency is obtained and its magnitude at some power factor.?, a detailed solution for 5.The iron loss and full load copper loss of 100KVA 6600/400V olts single phase transformer are 600W ats and 900 Watts.Calculate the efficiency at full load and half load at 0.8 power factor lag.Calculate the load at which maximum efficiency is obtained and its magnitude at some power factor.? has been provided alongside types of 5.The iron loss and full load copper loss of 100KVA 6600/400V olts single phase transformer are 600W ats and 900 Watts.Calculate the efficiency at full load and half load at 0.8 power factor lag.Calculate the load at which maximum efficiency is obtained and its magnitude at some power factor.? theory, EduRev gives you an
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