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The energy of a photon is given as 3.03 x 10-19 J/atom. The wavelength of the photon is
- a)6.56 nm
- b)65.6 nm
- c)0.656 nm
- d)656 nm
Correct answer is option 'D'. Can you explain this answer?
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The energy of a photon is given as 3.03 x 10-19 J/atom. The wavelength...
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The energy of a photon is given as 3.03 x 10-19 J/atom. The wavelength...
Energy of a Photon
The energy of a photon is given by the equation E = hf, where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J.s), and f is the frequency of the photon.
Energy of a Photon in terms of Wavelength
The frequency of a photon can be related to its wavelength through the equation c = λf, where c is the speed of light (3 x 10^8 m/s), λ is the wavelength of the photon, and f is the frequency of the photon. Rearranging this equation, we get f = c/λ.
Substituting this expression for f into the equation for the energy of a photon, we get E = h(c/λ).
Calculating the Wavelength of the Photon
Given that the energy of the photon is 3.03 x 10^-19 J/atom, we can substitute this value into the equation for the energy of a photon and solve for λ.
E = h(c/λ)
3.03 x 10^-19 J/atom = (6.626 x 10^-34 J.s)(3 x 10^8 m/s)/λ
Simplifying, we find:
λ = (6.626 x 10^-34 J.s)(3 x 10^8 m/s)/(3.03 x 10^-19 J/atom)
λ = 656 nm
Answer
Therefore, the wavelength of the photon is 656 nm.
The energy of a photon is given by the equation E = hf, where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J.s), and f is the frequency of the photon.
Energy of a Photon in terms of Wavelength
The frequency of a photon can be related to its wavelength through the equation c = λf, where c is the speed of light (3 x 10^8 m/s), λ is the wavelength of the photon, and f is the frequency of the photon. Rearranging this equation, we get f = c/λ.
Substituting this expression for f into the equation for the energy of a photon, we get E = h(c/λ).
Calculating the Wavelength of the Photon
Given that the energy of the photon is 3.03 x 10^-19 J/atom, we can substitute this value into the equation for the energy of a photon and solve for λ.
E = h(c/λ)
3.03 x 10^-19 J/atom = (6.626 x 10^-34 J.s)(3 x 10^8 m/s)/λ
Simplifying, we find:
λ = (6.626 x 10^-34 J.s)(3 x 10^8 m/s)/(3.03 x 10^-19 J/atom)
λ = 656 nm
Answer
Therefore, the wavelength of the photon is 656 nm.
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