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How much mass of silver nitrates will react with 5.85 g of sodium chloride to produce 14.35 g of silver chloride and 8.5 g of sodium nitrates if law of conservation of mass is followed?
- a)22.85 g
- b)108 g
- c)17.0 g
- d)28.70 g
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
How much mass of silver nitrates will react with 5.85 g of sodium chlo...
x + 5.85 = 8.5 + 14.35 ⇒ x = 17 g
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How much mass of silver nitrates will react with 5.85 g of sodium chlo...
Given:
Mass of sodium chloride (NaCl) = 5.85 g
Mass of silver chloride (AgCl) = 14.35 g
Mass of sodium nitrate (NaNO3) = 8.5 g
To find:
Mass of silver nitrate (AgNO3) that will react with NaCl.
Solution:
1. Write the balanced chemical equation for the reaction between NaCl and AgNO3 to form AgCl and NaNO3.
NaCl + AgNO3 → AgCl + NaNO3
2. Find the molar masses of the compounds involved in the reaction.
Molar mass of NaCl = 58.44 g/mol
Molar mass of AgNO3 = 169.87 g/mol
Molar mass of AgCl = 143.32 g/mol
Molar mass of NaNO3 = 84.99 g/mol
3. Convert the given masses of NaCl, AgCl, and NaNO3 into moles using their respective molar masses.
Moles of NaCl = 5.85 g / 58.44 g/mol = 0.1 mol
Moles of AgCl = 14.35 g / 143.32 g/mol = 0.1 mol
Moles of NaNO3 = 8.5 g / 84.99 g/mol = 0.1 mol
4. Use the mole ratio between NaCl and AgNO3 from the balanced chemical equation to find the moles of AgNO3 that reacted with NaCl.
From the balanced equation, 1 mole of NaCl reacts with 1 mole of AgNO3.
Therefore, moles of AgNO3 = moles of NaCl = 0.1 mol.
5. Convert the moles of AgNO3 into mass using its molar mass.
Mass of AgNO3 = moles of AgNO3 x molar mass of AgNO3
Mass of AgNO3 = 0.1 mol x 169.87 g/mol = 17.0 g
Therefore, the mass of silver nitrate that will react with 5.85 g of sodium chloride to produce 14.35 g of silver chloride and 8.5 g of sodium nitrate is 17.0 g. Hence, the correct option is (c) 17.0 g.
Mass of sodium chloride (NaCl) = 5.85 g
Mass of silver chloride (AgCl) = 14.35 g
Mass of sodium nitrate (NaNO3) = 8.5 g
To find:
Mass of silver nitrate (AgNO3) that will react with NaCl.
Solution:
1. Write the balanced chemical equation for the reaction between NaCl and AgNO3 to form AgCl and NaNO3.
NaCl + AgNO3 → AgCl + NaNO3
2. Find the molar masses of the compounds involved in the reaction.
Molar mass of NaCl = 58.44 g/mol
Molar mass of AgNO3 = 169.87 g/mol
Molar mass of AgCl = 143.32 g/mol
Molar mass of NaNO3 = 84.99 g/mol
3. Convert the given masses of NaCl, AgCl, and NaNO3 into moles using their respective molar masses.
Moles of NaCl = 5.85 g / 58.44 g/mol = 0.1 mol
Moles of AgCl = 14.35 g / 143.32 g/mol = 0.1 mol
Moles of NaNO3 = 8.5 g / 84.99 g/mol = 0.1 mol
4. Use the mole ratio between NaCl and AgNO3 from the balanced chemical equation to find the moles of AgNO3 that reacted with NaCl.
From the balanced equation, 1 mole of NaCl reacts with 1 mole of AgNO3.
Therefore, moles of AgNO3 = moles of NaCl = 0.1 mol.
5. Convert the moles of AgNO3 into mass using its molar mass.
Mass of AgNO3 = moles of AgNO3 x molar mass of AgNO3
Mass of AgNO3 = 0.1 mol x 169.87 g/mol = 17.0 g
Therefore, the mass of silver nitrate that will react with 5.85 g of sodium chloride to produce 14.35 g of silver chloride and 8.5 g of sodium nitrate is 17.0 g. Hence, the correct option is (c) 17.0 g.
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How much mass of silver nitrates will react with 5.85 g of sodium chloride to produce 14.35 g of silver chloride and 8.5 g of sodium nitrates if law of conservation of mass is followed?a)22.85 gb)108 gc)17.0 gd)28.70 gCorrect answer is option 'C'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about How much mass of silver nitrates will react with 5.85 g of sodium chloride to produce 14.35 g of silver chloride and 8.5 g of sodium nitrates if law of conservation of mass is followed?a)22.85 gb)108 gc)17.0 gd)28.70 gCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for How much mass of silver nitrates will react with 5.85 g of sodium chloride to produce 14.35 g of silver chloride and 8.5 g of sodium nitrates if law of conservation of mass is followed?a)22.85 gb)108 gc)17.0 gd)28.70 gCorrect answer is option 'C'. Can you explain this answer?.
How much mass of silver nitrates will react with 5.85 g of sodium chloride to produce 14.35 g of silver chloride and 8.5 g of sodium nitrates if law of conservation of mass is followed?a)22.85 gb)108 gc)17.0 gd)28.70 gCorrect answer is option 'C'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about How much mass of silver nitrates will react with 5.85 g of sodium chloride to produce 14.35 g of silver chloride and 8.5 g of sodium nitrates if law of conservation of mass is followed?a)22.85 gb)108 gc)17.0 gd)28.70 gCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for How much mass of silver nitrates will react with 5.85 g of sodium chloride to produce 14.35 g of silver chloride and 8.5 g of sodium nitrates if law of conservation of mass is followed?a)22.85 gb)108 gc)17.0 gd)28.70 gCorrect answer is option 'C'. Can you explain this answer?.
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How much mass of silver nitrates will react with 5.85 g of sodium chloride to produce 14.35 g of silver chloride and 8.5 g of sodium nitrates if law of conservation of mass is followed?a)22.85 gb)108 gc)17.0 gd)28.70 gCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for How much mass of silver nitrates will react with 5.85 g of sodium chloride to produce 14.35 g of silver chloride and 8.5 g of sodium nitrates if law of conservation of mass is followed?a)22.85 gb)108 gc)17.0 gd)28.70 gCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of How much mass of silver nitrates will react with 5.85 g of sodium chloride to produce 14.35 g of silver chloride and 8.5 g of sodium nitrates if law of conservation of mass is followed?a)22.85 gb)108 gc)17.0 gd)28.70 gCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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