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What mass of hydrochloric acid is needed to decompose 50 g of limestone?
  • a)
    36.5 g
  • b)
    73 g
  • c)
    50 g
  • d)
    100 g
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
What mass of hydrochloric acid is needed to decompose 50 g of limeston...

100 g of CaCO3 requires 73 g of HCl
∴ 50 g of CaCO3 requires 73/100 x 50 = 36.5 g of HCl
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Most Upvoted Answer
What mass of hydrochloric acid is needed to decompose 50 g of limeston...
The chemical equation for the reaction between hydrochloric acid and limestone (calcium carbonate) is:

HCl + CaCO3 -> CaCl2 + CO2 + H2O

From the equation, we can see that 1 mole of hydrochloric acid reacts with 1 mole of calcium carbonate. The molar mass of calcium carbonate is 100.09 g/mol.

To find the number of moles of calcium carbonate in 50 g, we divide the mass by the molar mass:

50 g / 100.09 g/mol = 0.4998 mol

This means that 0.4998 moles of hydrochloric acid are needed to react with 0.4998 moles of calcium carbonate.

The molar mass of hydrochloric acid is 36.46 g/mol. To find the mass of hydrochloric acid needed, we multiply the number of moles by the molar mass:

0.4998 mol x 36.46 g/mol = 18.23 g

Therefore, the mass of hydrochloric acid needed to decompose 50 g of limestone is 18.23 g, which is closest to option A, 36.5 g.
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What mass of hydrochloric acid is needed to decompose 50 g of limeston...
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What mass of hydrochloric acid is needed to decompose 50 g of limestone?a)36.5 gb)73 gc)50 gd)100 gCorrect answer is option 'A'. Can you explain this answer?
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