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An organic compound contains 80% (by wt.) carbon and the remaining percentage of hydrogen. The right option for the empirical formula of this compound is: [Atomic wt. of C is 12, H is 1] (2021)
- a)CH3
- b)CH4
- c)CH
- d)CH2
Correct answer is option 'A'. Can you explain this answer?
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An organic compound contains 80% (by wt.) carbon and the remaining per...
An empirical formula represents the simplest whole number ratio of various atoms present in a compound, whereas, the molecular formula shows the exact number of different types of atoms present in a molecule of a compound.
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An organic compound contains 80% (by wt.) carbon and the remaining per...
Given:
- An organic compound contains 80% (by wt.) carbon and the remaining percentage of hydrogen.
- Atomic wt. of C is 12, H is 1.
To find: The empirical formula of the compound.
Solution:
1. Assume a 100 g sample of the compound, which means it contains 80 g of carbon and 20 g of hydrogen.
2. Calculate the number of moles of each element:
- Moles of carbon = 80 g / 12 g/mol = 6.67 mol
- Moles of hydrogen = 20 g / 1 g/mol = 20 mol
3. Divide each mole value by the smallest mole value to get the simplest whole number ratio:
- Carbon: 6.67 mol / 6.67 mol = 1
- Hydrogen: 20 mol / 6.67 mol = 3
4. The empirical formula is therefore CH3, which has one carbon atom and three hydrogen atoms.
Therefore, the correct option is (a) CH3.
- An organic compound contains 80% (by wt.) carbon and the remaining percentage of hydrogen.
- Atomic wt. of C is 12, H is 1.
To find: The empirical formula of the compound.
Solution:
1. Assume a 100 g sample of the compound, which means it contains 80 g of carbon and 20 g of hydrogen.
2. Calculate the number of moles of each element:
- Moles of carbon = 80 g / 12 g/mol = 6.67 mol
- Moles of hydrogen = 20 g / 1 g/mol = 20 mol
3. Divide each mole value by the smallest mole value to get the simplest whole number ratio:
- Carbon: 6.67 mol / 6.67 mol = 1
- Hydrogen: 20 mol / 6.67 mol = 3
4. The empirical formula is therefore CH3, which has one carbon atom and three hydrogen atoms.
Therefore, the correct option is (a) CH3.
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An organic compound contains 80% (by wt.) carbon and the remaining percentage of hydrogen. The right option for the empirical formula of this compound is: [Atomic wt. of C is 12, H is 1] (2021)a)CH3b)CH4c)CHd)CH2Correct answer is option 'A'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An organic compound contains 80% (by wt.) carbon and the remaining percentage of hydrogen. The right option for the empirical formula of this compound is: [Atomic wt. of C is 12, H is 1] (2021)a)CH3b)CH4c)CHd)CH2Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An organic compound contains 80% (by wt.) carbon and the remaining percentage of hydrogen. The right option for the empirical formula of this compound is: [Atomic wt. of C is 12, H is 1] (2021)a)CH3b)CH4c)CHd)CH2Correct answer is option 'A'. Can you explain this answer?.
An organic compound contains 80% (by wt.) carbon and the remaining percentage of hydrogen. The right option for the empirical formula of this compound is: [Atomic wt. of C is 12, H is 1] (2021)a)CH3b)CH4c)CHd)CH2Correct answer is option 'A'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An organic compound contains 80% (by wt.) carbon and the remaining percentage of hydrogen. The right option for the empirical formula of this compound is: [Atomic wt. of C is 12, H is 1] (2021)a)CH3b)CH4c)CHd)CH2Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An organic compound contains 80% (by wt.) carbon and the remaining percentage of hydrogen. The right option for the empirical formula of this compound is: [Atomic wt. of C is 12, H is 1] (2021)a)CH3b)CH4c)CHd)CH2Correct answer is option 'A'. Can you explain this answer?.
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