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In a hydraulic lift, compressed air exerts a force F1 on a small piston having a radius of 5 cm. This pressure is transmitted to a second piston of radius 15 cm. If the mass of the load to be lifted is 1350 kg, then find the value of F1.
  • a)
    1.4 × 105 N
  • b)
    2 × 105 N
  • c)
    1.5 × 103 N
  • d)
    1.9 × 103 N
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
In a hydraulic lift, compressed air exerts a force F1 on a small pist...
Given:
Radius of small piston (r1) = 5 cm = 0.05 m
Radius of large piston (r2) = 15 cm = 0.15 m
Mass of the load (m) = 1350 kg

We need to find the value of force exerted by the compressed air on the small piston (F1).

Principle of Pascal's Law:
According to Pascal's law, the pressure applied to a fluid in a confined space is transmitted equally in all directions.

Formula:
F1/F2 = A1/A2
Where,
F1 = Force exerted on the small piston
F2 = Force exerted on the large piston
A1 = Area of the small piston
A2 = Area of the large piston

Calculation:
Area of the small piston (A1) = π * r1^2
= 3.14 * (0.05)^2
= 0.00785 m^2

Area of the large piston (A2) = π * r2^2
= 3.14 * (0.15)^2
= 0.07065 m^2

Using the formula F1/F2 = A1/A2, we can find the value of F1.

F1/F2 = A1/A2
F1 = (A1/A2) * F2

The force exerted on the large piston (F2) can be calculated using the formula F2 = m * g, where g is the acceleration due to gravity.

F2 = m * g
= 1350 kg * 9.8 m/s^2
= 13230 N

Substituting the values of A1, A2, and F2 in the formula, we get:

F1 = (0.00785 m^2 / 0.07065 m^2) * 13230 N
= 0.1111 * 13230 N
≈ 1470 N

Therefore, the value of F1 is approximately 1470 N, which is equal to 1.47 × 10^3 N.

Hence, the correct answer is option C) 1.5 × 10^3 N.
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Community Answer
In a hydraulic lift, compressed air exerts a force F1 on a small pist...
Since pressure is transmitted undiminished throughout the fluid (Pascal's law)
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In a hydraulic lift, compressed air exerts a force F1 on a small piston having a radius of 5 cm. This pressure is transmitted to a second piston of radius 15 cm. If the mass of the load to be lifted is 1350 kg, then find the value of F1.a)1.4 × 105 Nb)2 × 105 Nc)1.5 × 103 Nd)1.9 × 103 NCorrect answer is option 'C'. Can you explain this answer?
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