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A circular park of radius 10m is situated in a colony. Three boy's ankur, syed and David are sitting at equal distance on its boundary each having a toy telephone in his hand to talk each other. Find the length of the string of each phone?
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A circular park of radius 10m is situated in a colony. Three boy's ank...
Park and Boy's Position

The circular park has a radius of 10m. Let's assume the center of the park is point O. Ankur, Syed, and David are sitting at equal distances on the boundary of the park.

Equilateral Triangle

Since Ankur, Syed, and David are sitting at equal distances on the boundary of the park, they form an equilateral triangle. In an equilateral triangle, all sides are equal, and each angle is 60 degrees.

Connecting the Points

To connect Ankur, Syed, and David, we need to draw lines from each boy to the other two boys. These lines would represent the length of the string of each phone.

Length of the String

To find the length of the string of each phone, we can use the concept of trigonometry. In an equilateral triangle, the length of each side is equal. Let's assume the length of the string is 'x'.

Using Trigonometry

To find the length of the string, we can use the trigonometric ratio of sine. In a right-angled triangle formed by one of the boys, the center of the park, and one of the other boys, the sine of the angle formed at the center of the park is equal to the length of the string divided by the radius of the park.

sin(60) = x/10

Simplifying the equation:

√3/2 = x/10

x = (10 * √3)/2

x = 5√3 m

Length of the String

The length of the string of each phone is 5√3 meters.
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A circular park of radius 10m is situated in a colony. Three boy's ankur, syed and David are sitting at equal distance on its boundary each having a toy telephone in his hand to talk each other. Find the length of the string of each phone?
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