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निम्नलिखित गुणनफल पर विचार कीजिए। (x1+y1) (x2+y2)...(X10+y10)
उपर्युक्त गुणनफल को सरल करने पर ऐसे कितने पद प्राप्त होंगे जिनमें केवल एक x होगा?
  • a)
    10
  • b)
    210
  • c)
    1
  • d)
    20
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
(x1+y1)(x2+y2)...(X10+y10) x ?a)10b)210c)1d)20Correc...
हमें 10 पदों में से x का चयन करना है।
10 पदों में से 1 पद का चयन करने पर
= 10C1 = 10!/(1! x 9!)= 10
अभीष्ट पदों की संख्या 10 हैं।
इसलिए विकल्प (a) सही उत्तर है।
नोट: हम इस प्रश्न को इसके पैटर्न को देखकर भी हल कर सकते हैं।
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Community Answer
(x1+y1)(x2+y2)...(X10+y10) x ?a)10b)210c)1d)20Correc...

Explanation:

Given Data:
- Coordinates: (x1 y1), (x2 y2), ..., (x10 y10)

Question:
- Find the value of x

Calculation:
- Since the coordinates are given as (x1 y1), (x2 y2), ..., (x10 y10), we can see that x is common in all the pairs
- Therefore, x is the first value in each pair of coordinates

Answer:
- The value of x is 10

Therefore, the correct answer is option 'A' which is 10.
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