If a mode exceeds a mean by 12 then the mode exceeds the median by .a)4b)8c)6d)10Correct answer is option 'B'. Can you explain this answer?

Question

Answer

Given:
- Mode exceeds the mean by 12.
- Mode exceeds the median.

To Find:
The difference between the mode and the median.

Solution:
Let's consider a set of numbers to understand this concept better. Suppose we have the following set of numbers:

{2, 4, 4, 6, 8, 10, 10, 14}

In this set, the mode is 4 as it appears twice, while other numbers appear only once. The median is 6, which is the middle number when the set is arranged in ascending order.

Now, let's calculate the mean of this set:

Mean = (2 + 4 + 4 + 6 + 8 + 10 + 10 + 14) / 8
= 58 / 8
= 7.25

The mode exceeds the mean by 12, so the mode in this case would be 7.25 + 12 = 19.25.

Now, let's compare the mode and median:

Mode - Median = 19.25 - 6 = 13.25

Conclusion:
In the given scenario, the mode exceeds the median by 13.25. However, none of the options provided matches this value. Therefore, the correct answer cannot be determined from the given options.

Answer

Frequency of a particular class = cumulative frequency of that class -cumulative frequency of the previous class
= 50 - 30 = 20

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