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Find the steady state power limit of a system consisting of generator equivalent a reactance 0.5 pu connected to an infinite bus through a series reactance of 1 pu. The terminal voltage of the generator is held at 1.2 pu and the voltage of the infinite bus is 1?
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Find the steady state power limit of a system consisting of generator ...
Steady State Power Limit of a System
Introduction:
In electrical power systems, it is essential to determine the steady-state power limit of a system to ensure the safe and reliable operation of the generators and transmission lines. The steady-state power limit defines the maximum power that can be transferred between the generator and the infinite bus without causing voltage instability or exceeding the equipment ratings.
Given Data:
- Generator reactance (Xg) = 0.5 pu
- Series reactance (Xs) = 1 pu
- Terminal voltage of the generator (Vg) = 1.2 pu
- Voltage of the infinite bus (Vb) = 1 pu
Calculating Steady State Power Limit:
1. Impedance of the Series Reactance:
The impedance of the series reactance can be calculated using the formula:
Zs = jXs
Zs = j(1 pu)
Zs = j1
2. Impedance of the Generator:
The impedance of the generator can be calculated using the formula:
Zg = jXg
Zg = j(0.5 pu)
Zg = j0.5
3. Total Impedance:
The total impedance (Z) of the system can be calculated by adding the impedance of the generator and the series reactance:
Z = Zg + Zs
Z = j0.5 + j1
Z = j1.5
4. Current:
The current (I) flowing through the system can be calculated using Ohm's Law:
I = Vg / Z
I = 1.2 pu / j1.5
I = 0.8 - j0.53 pu
5. Real Power:
The real power (P) is given by the product of the generator voltage (Vg) and the real part of the current (I):
P = Vg * Re(I)
P = 1.2 pu * 0.8 pu
P = 0.96 pu
6. Reactive Power:
The reactive power (Q) is given by the product of the generator voltage (Vg) and the imaginary part of the current (I):
Q = Vg * Im(I)
Q = 1.2 pu * (-0.53 pu)
Q = -0.636 pu
Conclusion:
The steady-state power limit of the system, consisting of a generator with an equivalent reactance of 0.5 pu connected to an infinite bus through a series reactance of 1 pu, is determined to be 0.96 pu for real power and -0.636 pu for reactive power. These limits ensure the stable operation of the system without exceeding the equipment ratings or causing voltage instability.
Introduction:
In electrical power systems, it is essential to determine the steady-state power limit of a system to ensure the safe and reliable operation of the generators and transmission lines. The steady-state power limit defines the maximum power that can be transferred between the generator and the infinite bus without causing voltage instability or exceeding the equipment ratings.
Given Data:
- Generator reactance (Xg) = 0.5 pu
- Series reactance (Xs) = 1 pu
- Terminal voltage of the generator (Vg) = 1.2 pu
- Voltage of the infinite bus (Vb) = 1 pu
Calculating Steady State Power Limit:
1. Impedance of the Series Reactance:
The impedance of the series reactance can be calculated using the formula:
Zs = jXs
Zs = j(1 pu)
Zs = j1
2. Impedance of the Generator:
The impedance of the generator can be calculated using the formula:
Zg = jXg
Zg = j(0.5 pu)
Zg = j0.5
3. Total Impedance:
The total impedance (Z) of the system can be calculated by adding the impedance of the generator and the series reactance:
Z = Zg + Zs
Z = j0.5 + j1
Z = j1.5
4. Current:
The current (I) flowing through the system can be calculated using Ohm's Law:
I = Vg / Z
I = 1.2 pu / j1.5
I = 0.8 - j0.53 pu
5. Real Power:
The real power (P) is given by the product of the generator voltage (Vg) and the real part of the current (I):
P = Vg * Re(I)
P = 1.2 pu * 0.8 pu
P = 0.96 pu
6. Reactive Power:
The reactive power (Q) is given by the product of the generator voltage (Vg) and the imaginary part of the current (I):
Q = Vg * Im(I)
Q = 1.2 pu * (-0.53 pu)
Q = -0.636 pu
Conclusion:
The steady-state power limit of the system, consisting of a generator with an equivalent reactance of 0.5 pu connected to an infinite bus through a series reactance of 1 pu, is determined to be 0.96 pu for real power and -0.636 pu for reactive power. These limits ensure the stable operation of the system without exceeding the equipment ratings or causing voltage instability.
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Find the steady state power limit of a system consisting of generator equivalent a reactance 0.5 pu connected to an infinite bus through a series reactance of 1 pu. The terminal voltage of the generator is held at 1.2 pu and the voltage of the infinite bus is 1?
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Find the steady state power limit of a system consisting of generator equivalent a reactance 0.5 pu connected to an infinite bus through a series reactance of 1 pu. The terminal voltage of the generator is held at 1.2 pu and the voltage of the infinite bus is 1? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about Find the steady state power limit of a system consisting of generator equivalent a reactance 0.5 pu connected to an infinite bus through a series reactance of 1 pu. The terminal voltage of the generator is held at 1.2 pu and the voltage of the infinite bus is 1? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find the steady state power limit of a system consisting of generator equivalent a reactance 0.5 pu connected to an infinite bus through a series reactance of 1 pu. The terminal voltage of the generator is held at 1.2 pu and the voltage of the infinite bus is 1?.
Find the steady state power limit of a system consisting of generator equivalent a reactance 0.5 pu connected to an infinite bus through a series reactance of 1 pu. The terminal voltage of the generator is held at 1.2 pu and the voltage of the infinite bus is 1? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about Find the steady state power limit of a system consisting of generator equivalent a reactance 0.5 pu connected to an infinite bus through a series reactance of 1 pu. The terminal voltage of the generator is held at 1.2 pu and the voltage of the infinite bus is 1? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find the steady state power limit of a system consisting of generator equivalent a reactance 0.5 pu connected to an infinite bus through a series reactance of 1 pu. The terminal voltage of the generator is held at 1.2 pu and the voltage of the infinite bus is 1?.
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