A race track is in the form of a ring whose inner and outer circumfere...
To find the area of the track, we need to subtract the area of the inner circle from the area of the outer circle.
First, let's find the radius of the inner and outer circles using the given circumferences.
- The inner circumference is given as 437 m. We can use the formula for the circumference of a circle, C = 2πr, where C is the circumference and r is the radius. Plugging in the given value, we have:
437 = 2πr
Dividing both sides by 2π, we get:
r = 437 / (2π)
r ≈ 69.5 m
- The outer circumference is given as 50 m. Using the same formula, we have:
50 = 2πR
Dividing both sides by 2π, we get:
R = 50 / (2π)
R ≈ 7.96 m
Now that we have the radius of the inner circle (r) and the outer circle (R), we can find their areas.
- The area of a circle is given by the formula A = πr^2, where A is the area and r is the radius.
- The area of the inner circle is:
A_inner = πr^2
A_inner = π(69.5)^2
A_inner ≈ 15141.32 m^2
- The area of the outer circle is:
A_outer = πR^2
A_outer = π(7.96)^2
A_outer ≈ 199.16 m^2
Now, subtract the area of the inner circle from the area of the outer circle to find the area of the track:
Area of the track = A_outer - A_inner
Area of the track ≈ 199.16 m^2 - 15141.32 m^2
Area of the track ≈ -14942.16 m^2
Since the calculated area is negative, it means there might be an error in the given measurements or calculations. None of the provided answer options are correct.
A race track is in the form of a ring whose inner and outer circumfere...
Let R be the radius of outer circle and r be the radius of inner circle.
2πR = 503

and 2πr = 437

Width of the track = R - r =


Area of the track = π(R
2 - r
2)
= π(R+ r) (R - r)

= 4935 m
2