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If A and B are the roots of the quadratic equation x2 - 12x + 27 = 0, then A3 + B3 is
  • a)
    27
  • b)
    729
  • c)
    756
  • d)
    64
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
If A and B are the roots of the quadratic equation x2 - 12x + 27 = 0, ...
Given:
The quadratic equation is x^2 - 12x + 27 = 0

To find:
The value of A^3 + B^3

Solution:
We know that if A and B are the roots of a quadratic equation ax^2 + bx + c = 0, then the sum of the roots is given by A + B = -b/a and the product of the roots is given by AB = c/a.

So, in the given equation x^2 - 12x + 27 = 0, the sum of the roots A and B is A + B = 12 and the product of the roots A and B is AB = 27.

Now, let's find the value of (A^3 + B^3).

Step 1:
We know that (A + B)^3 = A^3 + B^3 + 3AB(A + B)

Substituting the given values, (A + B)^3 = (12)^3

Simplifying, (A + B)^3 = 1728

Step 2:
Expanding (A + B)^3, we get A^3 + 3A^2B + 3AB^2 + B^3 = 1728

Step 3:
Substituting the values of AB and simplifying, we get A^3 + B^3 + 3(27)(12) + 12(3)(27) = 1728

Simplifying further, we get A^3 + B^3 + 324 + 972 = 1728

Step 4:
Combining like terms, we get A^3 + B^3 + 1296 = 1728

Step 5:
Subtracting 1296 from both sides, we get A^3 + B^3 = 1728 - 1296

Simplifying, we get A^3 + B^3 = 432

Answer:
Therefore, the value of A^3 + B^3 is 432.
Free Test
Community Answer
If A and B are the roots of the quadratic equation x2 - 12x + 27 = 0, ...
Given A and B are the roots of x2 - 12x + 27 = 0
⇒ (x - 3)(x - 9) = 0
∴ A =  3, B = 9
Hence A3 + B3 = 33 + 93 = 27 + 729 = 756
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