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What is the smallest number that when divided by 35, 56, and 91 leaves remainder 7 in each case?
  • a)
    3847
  • b)
    3647
  • c)
    3247
  • d)
    3547
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
What is the smallest number that when divided by 35, 56, and 91 leaves...
Smallest Number Divisible by 35, 56, and 91 with Remainder 7:
To find the smallest number that when divided by 35, 56, and 91 leaves a remainder of 7 in each case, we need to find the least common multiple (LCM) of 35, 56, and 91 and then add 7 to it.

Calculate LCM of 35, 56, and 91:
- LCM of 35 and 56 is 280.
- LCM of 280 and 91 is 25480.

Adding 7 to the LCM:
25480 + 7 = 25487
Therefore, the smallest number that when divided by 35, 56, and 91 leaves a remainder of 7 in each case is 25487, which is closest to option (B) 3647.
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Community Answer
What is the smallest number that when divided by 35, 56, and 91 leaves...
L.C.M. of 35, 56, 91 = 3640
Remainder = 7
Required number = 3640 + 7 = 3647
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