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Two ml each of concentrated HCl, HNO3 and mixture of concentrated HCl and concentrated HNO3 in the ratio of 3 : 1 were taken in test tubes labelled as A, B and C. A small piece of metal was put in each test tube. No change occurred in test tubes A and B but the metal got dissolved in test tube C. The metal could be.
  • a)
    Au
  • b)
    Al
  • c)
    Pt
  • d)
    Cu
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Two ml each of concentrated HCl, HNO3 and mixture of concentrated HCl ...
Pt do not react with conc HCl or conc HNO3 but dissolves in a mixture of conc. HCl and conc. HNO3 in the ratio 3 :1 called aqua-regia)
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Two ml each of concentrated HCl, HNO3 and mixture of concentrated HCl and concentrated HNO3 in the ratio of 3 : 1 were taken in test tubes labelled as A, B and C. A small piece of metal was put in each test tube. No change occurred in test tubes A and B but the metal got dissolved in test tube C. The metal could be.a)Aub)Alc)Ptd)CuCorrect answer is option 'C'. Can you explain this answer? for Class 10 2025 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about Two ml each of concentrated HCl, HNO3 and mixture of concentrated HCl and concentrated HNO3 in the ratio of 3 : 1 were taken in test tubes labelled as A, B and C. A small piece of metal was put in each test tube. No change occurred in test tubes A and B but the metal got dissolved in test tube C. The metal could be.a)Aub)Alc)Ptd)CuCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 10 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two ml each of concentrated HCl, HNO3 and mixture of concentrated HCl and concentrated HNO3 in the ratio of 3 : 1 were taken in test tubes labelled as A, B and C. A small piece of metal was put in each test tube. No change occurred in test tubes A and B but the metal got dissolved in test tube C. The metal could be.a)Aub)Alc)Ptd)CuCorrect answer is option 'C'. Can you explain this answer?.
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