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Median of a given frequency distribution is found with the help of a –
  • a)
    Bar graph
  • b)
    Ogive
  • c)
    Histogram
  • d)
    None of these
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Median of a given frequency distribution is found with the help of a &...
Understanding Median in Frequency Distribution
The median is a crucial statistical measure that represents the middle value in a data set. In the context of frequency distribution, it helps in understanding the central tendency of the data.
Why Ogives are Used
An ogive is a graphical representation of the cumulative frequency of a dataset. It is particularly useful for finding the median because:
- Cumulative Frequency: An ogive plots cumulative frequencies against the upper boundaries of class intervals, allowing for quick identification of the median position.
- Visual Representation: By using an ogive, one can visually assess where the median lies. It shows the point at which 50% of the data lies below it.
- Intersection with the Median Line: To find the median from an ogive, a horizontal line is drawn at the 50% mark of the total frequency. The point where this line intersects the ogive indicates the median value.
Comparison with Other Methods
- Bar Graphs: While bar graphs display the frequency of individual categories, they do not provide cumulative data, making it difficult to extract the median.
- Histograms: Although histograms represent frequency distributions, they require additional calculations to determine the median, lacking the direct visual method offered by ogives.
- None of These: This option does not apply, as ogives are specifically designed for cumulative frequency analysis and median identification.
In conclusion, using an ogive is the most effective method for finding the median in a frequency distribution, making option 'B' the correct choice.
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Median of a given frequency distribution is found with the help of a –a)Bar graphb)Ogivec)Histogramd)None of theseCorrect answer is option 'B'. Can you explain this answer?
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