A spherical shell of mass m and radius R is pulled on s horizontal pla...
Assuming that the spherical shell is not slipping on the plane, the force of friction acting on the shell opposes the force F. Therefore, the net force acting on the shell is:
F_net = F - f
where f is the force of friction.
The force of friction is equal to the coefficient of friction μ multiplied by the normal force N, which is the force exerted by the plane on the shell and is equal to the weight of the shell:
f = μN = μmg
where μ is the coefficient of friction, m is the mass of the shell, and g is the acceleration due to gravity.
Since the shell is not accelerating vertically, the normal force N is equal to the weight of the shell:
N = mg
Therefore, the force of friction is:
f = μmg
The net force in the horizontal direction is:
F_net = F - f = F - μmg
According to Newton's second law, the acceleration of the shell is given by:
a = F_net / m = (F - μmg) / m
So, the acceleration of the shell depends on the magnitude of the force F, the mass of the shell, the coefficient of friction, and the acceleration due to gravity.