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At a particular temperature, the vapour pressures of two liquids A and B are respectively 120 and 180 mm of mercury. If 2 moles of A and 3 moles of B are mixed to form an ideal solution, the vapour pressure of the solution at the same temperature will be (in mm of mercury)
  • a)
    156
  • b)
    145
  • c)
    150
  • d)
    108
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
At a particular temperature, the vapour pressures of two liquids A an...
Given information:
- Vapour pressure of liquid A = 120 mmHg
- Vapour pressure of liquid B = 180 mmHg
- Moles of A = 2
- Moles of B = 3

To find: Vapour pressure of the solution

According to Raoult's law, the partial pressure of each component in the vapour phase of an ideal solution is directly proportional to its mole fraction in the solution.

Raoult's law equation for a binary mixture:
P_total = X_A * P_A + X_B * P_B

where P_total is the total vapour pressure of the solution, X_A and X_B are the mole fractions of A and B, and P_A and P_B are the vapour pressures of A and B, respectively.

Let's calculate the mole fractions of A and B:
Mole fraction of A = Moles of A / Total moles in the solution = 2 / (2 + 3) = 2/5
Mole fraction of B = Moles of B / Total moles in the solution = 3 / (2 + 3) = 3/5

Substituting the values in Raoult's law equation:
P_total = (2/5) * 120 + (3/5) * 180
P_total = 24 + 108
P_total = 132 mmHg

Therefore, the vapour pressure of the solution at the given temperature is 132 mmHg.

However, none of the provided answer options match the calculated value. It seems there might be an error in the options or the calculation.
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Community Answer
At a particular temperature, the vapour pressures of two liquids A an...
Vapour pressure of solution
= PA+ PB = PAoxA + PBoxB
=
= 156 mm
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At a particular temperature, the vapour pressures of two liquids A and B are respectively 120 and 180 mm of mercury. If 2 moles of A and 3 moles of B are mixed to form an ideal solution, the vapour pressure of the solution at the same temperature will be (in mm of mercury)a)156b)145c)150d)108Correct answer is option 'A'. Can you explain this answer?
Question Description
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