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If the sum of the product of the zeroes taken two at a time of the polynomial f(x) = 2x3 – 3x2 + 4tx – 5 is –8, then the value of t is _______.
  • a)
    2
  • b)
    4
  • c)
    –2
  • d)
    – 4 
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
If the sum of the product of the zeroes taken two at a time of the pol...
To find the sum of the product of the zeroes taken two at a time, we need to find the product of each pair of zeroes and then sum them up.

Let the zeroes of the polynomial f(x) = 2x^3 + px^2 + qx + r be a, b, and c.

The product of the zeroes taken two at a time can be expressed as:

ab + ac + bc

Using Vieta's formulas, we know that:

a + b + c = -p/2

ab + ac + bc = q/2

abc = -r/2

Now, we need to find the value of q/2.

From the given information, we can see that the coefficient of x term is q, which is the sum of the zeroes taken two at a time. Hence, q/2 is equal to the sum of the product of the zeroes taken two at a time.

Therefore, the sum of the product of the zeroes taken two at a time is q/2.
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Community Answer
If the sum of the product of the zeroes taken two at a time of the pol...
Given polynomial is 2x3 – 3x2 + 4tx – 5
Sum of product of roots taken two at a time is 4t/2.
∴ 4t/2 = -8 ⇒ t = –4
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