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If p, q are the zeroes of the polynomial f(x) = x2 + k(x – 1) – c, then (p – 1)(q – 1) is equal to _______.
  • a)
    c –1
  • b)
    1 – c
  • c)
    c
  • d)
    1 + c 
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
If p, q are the zeroes of the polynomial f(x) = x2 + k(x – 1) &n...
It seems like the question is incomplete. Could you please provide the complete expression for the polynomial f(x)?
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Community Answer
If p, q are the zeroes of the polynomial f(x) = x2 + k(x – 1) &n...
Given equation is x2 + k(x – 1) – c
= x2 + kx – (k + c)
Since, p and q are the zeroes,
∴ = – k and pq = – (k + c)
Now, (p – 1) (q – 1) = pq – q – p + 1
= pq – (p + q) + 1 = – (k + c) – (–k) + 1
= – k – c + k + 1 = 1 – c
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