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A mixture of 40 litres of alcohol and water contains 10% water. How much water (in litres) should be added to this mixture, so that the new mixture contains 20% water?
- a)9
- b)5
- c)7
- d)6
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
A mixture of 40 litres of alcohol and water contains 10% water. How m...
To solve this problem, let's first understand the given information.
Given:
- The mixture contains 40 liters of alcohol and water.
- The mixture is 10% water.
To find:
- The amount of water that should be added to the mixture to make it 20% water.
Let's assume that we need to add x liters of water to the mixture.
Step 1: Calculating the initial amount of water in the mixture.
Since the mixture is 10% water, the amount of water in the mixture can be calculated as:
10% of 40 liters = (10/100) * 40 = 4 liters
Step 2: Calculating the final amount of water in the new mixture.
After adding x liters of water, the total volume of the mixture will be (40 + x) liters.
The percentage of water in the new mixture is 20%.
Therefore, the amount of water in the new mixture can be calculated as:
20% of (40 + x) liters = (20/100) * (40 + x) = 8 + 0.2x liters
Step 3: Setting up the equation.
According to the given information, the amount of water in the new mixture should be equal to the initial amount of water plus the water added.
So, we have the equation:
4 liters + x liters = 8 + 0.2x liters
Simplifying the equation, we get:
x - 0.2x = 8 - 4
0.8x = 4
x = 4/0.8
x = 5 liters
Therefore, 5 liters of water should be added to the mixture to make it 20% water.
Hence, the correct answer is option B) 5.
Given:
- The mixture contains 40 liters of alcohol and water.
- The mixture is 10% water.
To find:
- The amount of water that should be added to the mixture to make it 20% water.
Let's assume that we need to add x liters of water to the mixture.
Step 1: Calculating the initial amount of water in the mixture.
Since the mixture is 10% water, the amount of water in the mixture can be calculated as:
10% of 40 liters = (10/100) * 40 = 4 liters
Step 2: Calculating the final amount of water in the new mixture.
After adding x liters of water, the total volume of the mixture will be (40 + x) liters.
The percentage of water in the new mixture is 20%.
Therefore, the amount of water in the new mixture can be calculated as:
20% of (40 + x) liters = (20/100) * (40 + x) = 8 + 0.2x liters
Step 3: Setting up the equation.
According to the given information, the amount of water in the new mixture should be equal to the initial amount of water plus the water added.
So, we have the equation:
4 liters + x liters = 8 + 0.2x liters
Simplifying the equation, we get:
x - 0.2x = 8 - 4
0.8x = 4
x = 4/0.8
x = 5 liters
Therefore, 5 liters of water should be added to the mixture to make it 20% water.
Hence, the correct answer is option B) 5.
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Community Answer
A mixture of 40 litres of alcohol and water contains 10% water. How m...
40 liters of mixture contains 4 liters of water (10%). So, it has 36 liters of milk.if 36 liters = 80%,of total mixture.
The 
liters So, the total water in the mixture should be 9 liters.
liters So, the total water in the mixture should be 9 liters.since there is already 4 liters in the mixture, 5 liters need to be added.
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A mixture of 40 litres of alcohol and water contains 10% water. How much water (in litres) should be added to this mixture, so that the new mixture contains 20% water?a)9b)5c)7d)6Correct answer is option 'B'. Can you explain this answer?
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