Two dice are thrown simultaneously. The probability of getting a doubl...
To find the probability of getting a doublet or a total of 4 when two dice are thrown simultaneously, we need to determine the number of favorable outcomes and the total number of possible outcomes.
Number of favorable outcomes:
1. Doublet: A doublet means both dice show the same number. There are six possible outcomes for a doublet - (1, 1), (2, 2), (3, 3), (4, 4), (5, 5), and (6, 6).
2. Total of 4: To get a total of 4, there are three possible outcomes - (1, 3), (2, 2), and (3, 1).
Therefore, the number of favorable outcomes is 6 (for doublets) + 3 (for a total of 4) = 9.
Total number of possible outcomes:
When two dice are thrown simultaneously, each die has 6 possible outcomes. Since both dice are thrown together, the total number of possible outcomes is 6 x 6 = 36.
Probability:
Probability = Number of favorable outcomes / Total number of possible outcomes
Therefore, the probability of getting a doublet or a total of 4 is 9/36, which simplifies to 1/4.
To convert 1/4 into a multiple of 9, we can multiply both the numerator and denominator by 9.
1/4 * 9/9 = 9/36
So, the probability of getting a doublet or a total of 4 is 9/36, which is equal to 2/9.
Hence, the correct answer is option A, 2/9.
Two dice are thrown simultaneously. The probability of getting a doubl...
Total number of outcomes, when two dice are thrown = 6 x 6 = 36
Total number of doublets present = (1,1), (2, 2), (3, 3), (4, 4), (5, 5), (6,6)
For a total of 4, pairs can be (1,3), (3, 1), (2, 2).
= 8 [since (2, 2) is present in both the cases],
∴ Required probability = 8/36 = 2/9