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There is a solid sphere of radius R having uniformly distributed charge throughout it. What is the relation between electric field E and distance r from the centre (r < R)?
  • a)
    E ∝ r-2
  • b)
    E ∝ r-1
  • c)
    E ∝ r
  • d)
    E ∝ r2
Correct answer is option 'C'. Can you explain this answer?
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There is a solid sphere of radius R having uniformly distributed charg...
The electric field inside a uniformly charged solid sphere is given by:

E = 0 for r < />
E = k * (Q / r^2) for r ≥ R

Where:
E is the electric field strength,
k is the electrostatic constant (k = 9 x 10^9 N m^2/C^2),
Q is the total charge of the sphere,
r is the distance from the center of the sphere.

Inside the sphere (r < r),="" the="" electric="" field="" is="" zero="" because="" the="" charges="" cancel="" each="" other="" />

Outside the sphere (r ≥ R), the electric field is inversely proportional to the square of the distance from the center of the sphere. The total charge Q is spread uniformly throughout the sphere, so the electric field follows the same pattern as that of a point charge, where the electric field is given by k * (Q / r^2).
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