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An experiment was set up to determine the percentage of water absorbed by raisins. If the mass of dry raisins was 40 g and mass of wet raisins was 45 g, the percent water absorbed would be 
  • a)
    (45/40) x 100
  • b)
    (40/45) x 100
  • c)
  • d)
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
An experiment was set up to determine the percentage of water absorbed...
W1 = initial weight of raisins, 40 g
W2 = final weight of wet raisins, 45 g
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An experiment was set up to determine the percentage of water absorbed by raisins. If the mass of dry raisins was 40 g and mass of wet raisins was 45 g, the percent water absorbed would bea)(45/40) x 100b)(40/45) x 100c)d)Correct answer is option 'C'. Can you explain this answer?
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An experiment was set up to determine the percentage of water absorbed by raisins. If the mass of dry raisins was 40 g and mass of wet raisins was 45 g, the percent water absorbed would bea)(45/40) x 100b)(40/45) x 100c)d)Correct answer is option 'C'. Can you explain this answer? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about An experiment was set up to determine the percentage of water absorbed by raisins. If the mass of dry raisins was 40 g and mass of wet raisins was 45 g, the percent water absorbed would bea)(45/40) x 100b)(40/45) x 100c)d)Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An experiment was set up to determine the percentage of water absorbed by raisins. If the mass of dry raisins was 40 g and mass of wet raisins was 45 g, the percent water absorbed would bea)(45/40) x 100b)(40/45) x 100c)d)Correct answer is option 'C'. Can you explain this answer?.
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