UPSC Exam  >  UPSC Questions  >  +3.5 -2.5 ?a)1 b)100 c)-16.... Start Learning for Free
+3.5 डी और -2.5 डी शक्ति के दो पतले लेंस संपर्क में रखे गए हैं। लेंस संयोजन की फोकस दूरी ज्ञात कीजिए?
  • a)
    1 सेमी
  • b)
    100 सेमी
  • c)
    -16.7 वर्ग मीटर
  • d)
    16.7 वर्ग मीटर
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
+3.5 -2.5 ?a)1 b)100 c)-16.7 d)16.7 Correct answer...
Understanding the Problem
To solve the expression "+3.5 - 2.5", we need to perform basic arithmetic operations. This involves adding and subtracting the given numbers.
Step-by-Step Calculation
- Start with the first number: 3.5
- Subtract the second number: 2.5
Calculation Process
- 3.5 - 2.5 = 1.0
Thus, the result of the operation is 1.
Explaining the Options
Now, let's analyze the options provided:
- a) 1: This is the result of our calculation.
- b) 100: This is not related to the arithmetic operation we performed.
- c) -16.7: This is a negative number and also not relevant to our calculation.
- d) 16.7: Again, this does not correlate with the numbers we are working with.
Conclusion
The correct answer to the expression "+3.5 - 2.5" is option 'a', which is 1. The assertion that option 'b' (100) is correct is incorrect.
In summary, the solution to the expression is straightforward arithmetic, leading us to conclude that the right answer is indeed 1, not 100.
Free Test
Community Answer
+3.5 -2.5 ?a)1 b)100 c)-16.7 d)16.7 Correct answer...
लेंस की क्षमता एक = P1 = +3.5D (दिया गया)
लेंस की शक्ति दो = P2 = -2.5D (दिया गया)
शक्ति संयोजन = P1 + P2

इस प्रकार,
संयोजन की शक्ति = +3.5 डी +(-2.5 डी )
= 3.5 डी -2.5 डी
= 1 डी

शक्ति = 1/फोकल लंबाई (एम)  
 1 = 1/f
 f = 1/1
 f = 1 मीटर
इस प्रकार, संयोजन का f = 1×100 = 100 सेमी

इसलिए, यदि +3.5D और -2.5D शक्ति के दो पतले लेंस संपर्क में रखे जाते हैं तो लेंस संयोजन की शक्ति और फोकल लंबाई 100 cm होगी।
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