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A test-tube contains a colourless solution of potassium iodide. The presence of iodine can be tested by:
  • a)
    adding a few drops of blue litmus solution.
  • b)
    adding a few drops of copper sulphate solution.
  • c)
    passing carbon dioxide gas through the solution.
  • d)
    passing chlorine gas through the solution.
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
A test-tube contains a colourless solution of potassium iodide. The pr...
Testing for Iodine Presence
When testing for the presence of iodine in a potassium iodide solution, the most effective method is to pass chlorine gas through it. Here's a detailed explanation of why option 'D' is correct.
Understanding Potassium Iodide
- Potassium iodide (KI) is a salt that contains potassium ions and iodide ions (I-).
- In its colourless solution, iodine is not present in its elemental form but can be liberated under certain conditions.
Role of Chlorine Gas
- Chlorine gas (Cl2) is a strong oxidizing agent.
- When chlorine gas is introduced into the potassium iodide solution, it oxidizes the iodide ions (I-) to elemental iodine (I2).
Color Change Indication
- The formation of elemental iodine results in a distinct color change.
- Iodine in solution exhibits a brownish color, which is a clear indication of its presence.
Why Other Options Are Incorrect
- Option A (Blue Litmus): This tests acidity or basicity, not iodine presence.
- Option B (Copper Sulphate): This does not react specifically with iodine and will not indicate its presence.
- Option C (Carbon Dioxide): Passing CO2 does not lead to a reaction with iodide ions and will not yield any color change.
Conclusion
Thus, passing chlorine gas through a potassium iodide solution is a reliable method to confirm the presence of iodine, leading to a color change that indicates a successful test.
Free Test
Community Answer
A test-tube contains a colourless solution of potassium iodide. The pr...
Chlorine will displace iodine from solution containing potassium iodide since it is more reactive than iodine. The liberated iodine will impart violet colour to the solution.
2KI (aq) + Cl2 (g) → 2 KCl (aq) + I2(g)
(violet)
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A test-tube contains a colourless solution of potassium iodide. The presence of iodine can be tested by:a)adding a few drops of blue litmus solution.b)adding a few drops of copper sulphate solution.c)passing carbon dioxide gas through the solution.d)passing chlorine gas through the solution.Correct answer is option 'D'. Can you explain this answer?
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