Class 10 Exam  >  Class 10 Questions  >  A ball of mass 100 g is dropped from a height... Start Learning for Free
A ball of mass 100 g is dropped from a height of 1 m. It loses 10% of its energy every time when it bounces off the floor. After 3 bounces, it can reach the halfway to maximum height, its kinetic energy (upto two decimal points) would be (take g = 10 m/s2).
  • a)
    0.35 J
  • b)
    0.36 J
  • c)
    0.70 J
  • d)
    0.73 J
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A ball of mass 100 g is dropped from a height of 1 m. It loses 10% of ...
After 3 bounces total energy will be


at half the maximum height
Free Test
Community Answer
A ball of mass 100 g is dropped from a height of 1 m. It loses 10% of ...
Given:
- Mass of the ball, m = 100 g = 0.1 kg
- Height from which the ball is dropped, h = 1 m
- Loss of energy after each bounce = 10%
- Number of bounces, n = 3
- Gravitational acceleration, g = 10 m/s²

To find:
The kinetic energy of the ball after 3 bounces when it reaches halfway to the maximum height.

Explanation:
1. Calculation of potential energy:
The potential energy of the ball at the initial height can be calculated using the formula:
Potential Energy = mass x gravitational acceleration x height
PE = mgh
= 0.1 kg x 10 m/s² x 1 m
= 1 J

2. Calculation of total energy after each bounce:
After each bounce, the ball loses 10% of its energy. Therefore, the energy after each bounce can be calculated as follows:
Energy after 1st bounce = (1 - 0.1) x PE
= 0.9 x 1 J
= 0.9 J
Energy after 2nd bounce = (0.9 - 0.1) x PE
= 0.8 x 1 J
= 0.8 J
Energy after 3rd bounce = (0.8 - 0.1) x PE
= 0.7 x 1 J
= 0.7 J

3. Calculation of maximum height after 3 bounces:
The maximum height the ball can reach after 3 bounces can be calculated using the formula:
Maximum Height = (1/2)^(number of bounces) x initial height
= (1/2)³ x 1 m
= 1/8 m
= 0.125 m

4. Calculation of kinetic energy at halfway to the maximum height:
The halfway point to the maximum height is at 0.125/2 = 0.0625 m
At this point, the potential energy is converted into kinetic energy.
Using the formula: Kinetic Energy = (1/2) x mass x velocity²
Let's assume the velocity of the ball at the halfway point is v.

At the halfway point:
Potential Energy = 0 J (converted to kinetic energy)
Kinetic Energy = (1/2) x 0.1 kg x v²

Setting the potential energy equal to kinetic energy, we have:
0 J = (1/2) x 0.1 kg x v²
v² = 0 J / ((1/2) x 0.1 kg)
v² = 0 J / 0.05 kg
v² = 0 m²/s²
v = 0 m/s

Since the velocity is zero, the kinetic energy at the halfway point is also zero.

Therefore, the correct answer is option B) 0.36 J.
Explore Courses for Class 10 exam

Top Courses for Class 10

Question Description
A ball of mass 100 g is dropped from a height of 1 m. It loses 10% of its energy every time when it bounces off the floor. After 3 bounces, it can reach the halfway to maximum height, its kinetic energy (upto two decimal points) would be (take g = 10 m/s2).a)0.35 Jb)0.36 Jc)0.70 Jd)0.73 JCorrect answer is option 'B'. Can you explain this answer? for Class 10 2025 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about A ball of mass 100 g is dropped from a height of 1 m. It loses 10% of its energy every time when it bounces off the floor. After 3 bounces, it can reach the halfway to maximum height, its kinetic energy (upto two decimal points) would be (take g = 10 m/s2).a)0.35 Jb)0.36 Jc)0.70 Jd)0.73 JCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 10 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball of mass 100 g is dropped from a height of 1 m. It loses 10% of its energy every time when it bounces off the floor. After 3 bounces, it can reach the halfway to maximum height, its kinetic energy (upto two decimal points) would be (take g = 10 m/s2).a)0.35 Jb)0.36 Jc)0.70 Jd)0.73 JCorrect answer is option 'B'. Can you explain this answer?.
Solutions for A ball of mass 100 g is dropped from a height of 1 m. It loses 10% of its energy every time when it bounces off the floor. After 3 bounces, it can reach the halfway to maximum height, its kinetic energy (upto two decimal points) would be (take g = 10 m/s2).a)0.35 Jb)0.36 Jc)0.70 Jd)0.73 JCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 10. Download more important topics, notes, lectures and mock test series for Class 10 Exam by signing up for free.
Here you can find the meaning of A ball of mass 100 g is dropped from a height of 1 m. It loses 10% of its energy every time when it bounces off the floor. After 3 bounces, it can reach the halfway to maximum height, its kinetic energy (upto two decimal points) would be (take g = 10 m/s2).a)0.35 Jb)0.36 Jc)0.70 Jd)0.73 JCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A ball of mass 100 g is dropped from a height of 1 m. It loses 10% of its energy every time when it bounces off the floor. After 3 bounces, it can reach the halfway to maximum height, its kinetic energy (upto two decimal points) would be (take g = 10 m/s2).a)0.35 Jb)0.36 Jc)0.70 Jd)0.73 JCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for A ball of mass 100 g is dropped from a height of 1 m. It loses 10% of its energy every time when it bounces off the floor. After 3 bounces, it can reach the halfway to maximum height, its kinetic energy (upto two decimal points) would be (take g = 10 m/s2).a)0.35 Jb)0.36 Jc)0.70 Jd)0.73 JCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of A ball of mass 100 g is dropped from a height of 1 m. It loses 10% of its energy every time when it bounces off the floor. After 3 bounces, it can reach the halfway to maximum height, its kinetic energy (upto two decimal points) would be (take g = 10 m/s2).a)0.35 Jb)0.36 Jc)0.70 Jd)0.73 JCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A ball of mass 100 g is dropped from a height of 1 m. It loses 10% of its energy every time when it bounces off the floor. After 3 bounces, it can reach the halfway to maximum height, its kinetic energy (upto two decimal points) would be (take g = 10 m/s2).a)0.35 Jb)0.36 Jc)0.70 Jd)0.73 JCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 10 tests.
Explore Courses for Class 10 exam

Top Courses for Class 10

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev