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A 10 V battery is connected to a series combination of two resistances of 4000 Ω and 6000 Ω. A non-ideal voltmeter of resistance 10,000 Ω connected across 4000 Ω reads 3.226 V. What would be the value if the same voltmeter connected across 6000 Ω?
- a)3.326 V
- b)4.326 V
- c)3.238 V
- d)4.838 V
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
A 10 V battery is connected to a series combination of two resistances...
The circuit diagram can be represented as follows:
```
___ 4000 Ω ___ 6000 Ω ___
| |
10 V 10,000 Ω
| |
--------------------------
```
From the given information, we can calculate the current flowing through the circuit using Ohm's Law:
V = I * R
Where V is the voltage, I is the current, and R is the resistance.
For the 4000 Ω resistor:
3.226 V = I * 4000 Ω
I = 3.226 V / 4000 Ω
I = 0.0008065 A
Now, let's calculate the voltage across the 6000 Ω resistor using the current calculated above:
V = I * R
V = 0.0008065 A * 6000 Ω
V ≈ 4.839 V
Hence, the value of the voltmeter reading across the 6000 Ω resistor would be approximately 4.839 V.
Therefore, the correct answer is option 'D' (4.838 V).
```
___ 4000 Ω ___ 6000 Ω ___
| |
10 V 10,000 Ω
| |
--------------------------
```
From the given information, we can calculate the current flowing through the circuit using Ohm's Law:
V = I * R
Where V is the voltage, I is the current, and R is the resistance.
For the 4000 Ω resistor:
3.226 V = I * 4000 Ω
I = 3.226 V / 4000 Ω
I = 0.0008065 A
Now, let's calculate the voltage across the 6000 Ω resistor using the current calculated above:
V = I * R
V = 0.0008065 A * 6000 Ω
V ≈ 4.839 V
Hence, the value of the voltmeter reading across the 6000 Ω resistor would be approximately 4.839 V.
Therefore, the correct answer is option 'D' (4.838 V).
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Community Answer
A 10 V battery is connected to a series combination of two resistances...
Req = 7750 Ω
i = 10/7750
v1 = (10/7750) x 4000 = 5.16
So v2 = 10 – 5.16
v2 = 4.838.
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A 10 V battery is connected to a series combination of two resistances of 4000 and 6000 . A non-ideal voltmeter of resistance 10,000 connected across 4000 reads 3.226 V. What would be the value if the same voltmeter connected across 6000 ?a)3.326 Vb)4.326 Vc)3.238 Vd)4.838 VCorrect answer is option 'D'. Can you explain this answer?
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A 10 V battery is connected to a series combination of two resistances of 4000 and 6000 . A non-ideal voltmeter of resistance 10,000 connected across 4000 reads 3.226 V. What would be the value if the same voltmeter connected across 6000 ?a)3.326 Vb)4.326 Vc)3.238 Vd)4.838 VCorrect answer is option 'D'. Can you explain this answer? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about A 10 V battery is connected to a series combination of two resistances of 4000 and 6000 . A non-ideal voltmeter of resistance 10,000 connected across 4000 reads 3.226 V. What would be the value if the same voltmeter connected across 6000 ?a)3.326 Vb)4.326 Vc)3.238 Vd)4.838 VCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 10 V battery is connected to a series combination of two resistances of 4000 and 6000 . A non-ideal voltmeter of resistance 10,000 connected across 4000 reads 3.226 V. What would be the value if the same voltmeter connected across 6000 ?a)3.326 Vb)4.326 Vc)3.238 Vd)4.838 VCorrect answer is option 'D'. Can you explain this answer?.
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