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Consider a class of 40 students whose average weight is 40 kgs. m new students join this class whose average weight is n kgs. If it is known that m + n = 50, what is the maximum possible average weight of the class now?

  • a)
    40.18 Kgs

  • b)
    40.56 Kgs

  • c)
    40.67 Kgs

  • d)
    40.49 Kgs

Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Consider a class of 40 students whose average weight is 40 kgs. m new ...
Solution:

Given, the class has 40 students with an average weight of 40 kgs.

Let the total weight of these 40 students be W1.

W1 = 40 x 40 = 1600 kgs

Now, m new students join the class with an average weight of n kgs.

Let the total weight of these m students be W2.

W2 = m x n

Also, m x n = 50

So, n = 50/m

Total number of students in the class now = 40 + m

Let the new average weight of the class be x kgs.

Then, we can write:

x = (W1 + W2)/(40 + m)

Substituting the values of W1 and W2, we get:

x = (1600 + mn)/(40 + m)

Substituting n = 50/m, we get:

x = (1600 + 50)/(40 + m)

x = (1650)/(40 + m)

To find the maximum value of x, we need to differentiate it with respect to m and equate it to zero.

dx/dm = -1650/(40 + m)^2 = 0

40 + m = sqrt(1650)

m = sqrt(1650) - 40

Substituting this value of m in the equation for x, we get:

x = 40 + (50/sqrt(1650) - 1)

x = 40.56 kgs (approx)

Therefore, the maximum possible average weight of the class now is 40.56 kgs (option B).
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Community Answer
Consider a class of 40 students whose average weight is 40 kgs. m new ...
If the overall average weight has to increase after the new people are added, the average weight of the new entrants has to be higher than 40.
So, n > 40
Consequently, m has to be < 10 (as n + m = 50)
Working with the “differences"? approach, we know that the total additional weight added by “m"? students would be (n - 40) each, above the already existing average of 40. m(n - 40) is the total extra additional weight added, which is shared amongst 40 + m students.
So, m * (n−40)(m+40)(n−40)(m+40) has to be maximum for the overall average to be maximum.

At this point, use the trial and error approach (or else, go with the answer options) to arrive at the answer.
The maximum average occurs when m = 5, and n = 45

And the average is 40 + (45 – 40) * 545545 = 40 + 5959 = 40.56 kgs
The question is "what is the maximum possible average weight of the class now?"
Hence, the answer is "40.56 kgs".
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Consider a class of 40 students whose average weight is 40 kgs. m new students join this class whose average weight is n kgs. If it is known that m + n = 50, what is the maximum possible average weight of the class now?a)40.18 Kgsb)40.56 Kgsc)40.67 Kgsd)40.49 KgsCorrect answer is option 'B'. Can you explain this answer?
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